 Hello and welcome to the session I am Deepika here. Let's discuss the question which says a chord of a circle of radius 10 centimeter subtends a right angle at the center. Find the area of the corresponding 1 minus segment 2 major sector. Use pi is equal to 3.14. Let us first recall the area of a sector of a circle. Now the portion of the circular region enclosed by 2 radii and the corresponding r is called the sector of the circle. Now in this figure the region, the circular region called the minor sector called the major sector of the major sector is 360 degree minus angle AOP. The area of the major sector circle that is pi r square minus area of the minor sector OAPB. The region between the corresponding r is called a segment of the circle. The region the major segment. Now area of the minor segment we will take the help of this key idea to solve the above question. So let's start the solution. Part 1 we have to find the area of the minor segment. For this first we will find the area of a sector is 90 degree. Sector is equal to O upon 360 into pi r square. Now theta is given to us 90 degree. So this is equal to 90 upon 360 into pi is equal to 10 upon 4 into 10 into 10 centimeter square. So on cancellation we have this is equal to 157 upon 2 centimeter square or this is equal to 78.5 centimeter square. Now area of the major sector angle AOP. Now this is a right triangle because angle AOP is 90 degree. So this is equal to 1 by 2 into base into height. Now base is 10 centimeter and height is also 10 centimeter. So this is equal to 1 by 2 into 10 into 10 centimeter square. So this is equal to 50 centimeter square. Now according to our key idea area of minor segment is equal to area of sector OAPB minus area of triangle AOP. Now this is equal to now area of sector is equal to 78.5 centimeter square minus area of triangle AOP is 50 centimeter square. So this is equal to 28.5 centimeter square. Part 2 in part 2 we have to find the area of major sector OAQB. Now we know that area of major sector is equal to area of circle minus area of minor sector OAPB. Now area of circle is equal to pi R square minus area of minor sector OAPB is theta upon 360 into pi R square. Now take pi is equal to 3.14. So this is 3.14 into 10 into 10 minus 90 upon 360 into 3.14 into 10 into 10 centimeter square. So this is equal to 3.14 minus 1 by 4 into 3.14 centimeter square and this is equal to 3.14 minus 78.5 centimeter square or this is equal to 235.5 centimeter square. Hence the area of the major sector is 235.5 centimeter square. Hence the answer for part 1 is 28.5 centimeter square and for part 2 is 235.5 centimeter square. I hope the solution is clear to you. Bye and take care.