 Hello and welcome to the session I am Deepika here. Let's discuss a question which says, choose the correct option and give justification. In given figure, if Tp and Tq are the two tangents to a circle with centered O so that angle P Oq is equal to 110 degree then angle P Tq is equal to A 60 degree, B 70 degree, C 80 degree and D 90 degree. So let's start the solution. Now given Tp and Tq are the two tangents to a circle with centered O. Therefore, Tp is equal to Tq because the lengths of tangents drawn from an external point to a circle are equal. Let us give this as number one, in given angle P Oq is equal to 110 degree, now join O T. Now we know that the tangent at any point of a circle is perpendicular to the radius to the point of contact. Therefore, angle O P T is 90 degree similarly, angle Oq T is 90 degree. So in right angle T O P and T Oq we have again O T is equal to O P common. So by RHS is congruent to triangle by sector of angle P O 110 degree as 90 degree and angle T O Pq as 55 degree. So we have angle P T plus 55 degree because the sum of the three angles of a triangle is 180 degree. Angle P T O is equal to 35 degree plus 35 degree which is equal to 70 degree. Since our option B is correct and this is our answer. I hope the solution is clear to you. Bye and take care.