 Hello and welcome to the session. In this session we discussed the following question which says, determine the 8th term from the end of the AP 4914 and so on up to 254. Now we are given one AP and we have to find the 8th term from the end of the given AP. Now the nth term from the end of the AP is given as l minus n minus 1 into d where this l is the last term of the AP and d is the common difference of the AP. This is the key idea that we use in this question. Now let's see the solution. The AP given to us is 4914 and so on up to 254. So here the last term l is 254. The common difference d is equal to 9 minus 4 which is equal to 5. And its term from the end is l minus n minus 1 whole into d and we have to find the 8th term from the end. So here we would take n as 8. So 8th term from the end of the given AP is equal to l minus 8 minus 1 into d. Now we put the values for l and d. So we get this is equal to 254 minus 7 into 5 that is 254 minus 35 which is equal to 219. So the 8th term from the end of the given AP is 219. So 219 is the required answer. This completes the session. Hope you have understood the solution of this question.