 Hello and welcome to the session. In this session we discuss a question which says that write a recursive formula for the sequence. Now before starting the solution of this question we should know a result and that is the recursive formula for an arithmetic sequence is given by a n is equal to a n minus 1 plus d where n is greater than 1. d is the common difference also first term of the sequence that is a 1 is known. Now this result will work out as a key idea for solving out the given question. Now let us start with the solution of the given question. Now in this question we have to find recursive formula for the given sequence. So first we determine whether the given sequence is arithmetic or geometric. Now let us see the difference between the two consecutive terms of the sequence. Now first time in the sequence is 8 and second term is 17 that is a 1 is 8 and a 2 is 17. So a 2 minus a 1 is equal to 17 minus 8 that is equal to 9. Then third term that is a 3 is 26. So a 3 minus a 2 is equal to 26 minus 17 that is again 9. Then first term is 35. So a 4 is 35. Now a 4 minus a 3 will be equal to 35 minus 26 that is again 9 and so on. Thus there is a common difference denoted by d between the consecutive terms of the sequence and the common difference d is equal to 9. Thus it is an arithmetic sequence. We have used the result which is given to us in the key idea. Now using the result which is given on the key idea we have in general the recursive formula for an arithmetic sequence a n is equal to a n minus 1 plus d where n is greater than 1 and d is the common difference. Now here we have d is equal to 9. So we put d is equal to 9 in this formula a n is equal to a n minus 1 plus 9 where n is greater than 1 also. First term of the sequence is given to us as so a 1 is equal to 8 thus the recursive formula for the given sequence is given by a 1 is equal to 8 a n is equal to a n minus 1 plus 9 where n is greater than 1. So this is the solution of the given question. That's all for this session. Hope you all have enjoyed this session.