 In this video, we provide the solution to question number 10 for practice exam number four for Math 1030, in which case we have the following situation. There are six colors in a bag of M&Ms and these colors are red, yellow, green, blue, orange and brown. According to the company's website, the probability of picking a yellow one is 14%. The probability of a green one is likewise 14%. The probability of an orange one is 20% and the probability of a blue one is 24%. Like this is four of the probabilities. If the probability of picking a red one is equal to the probability of picking a brown one, what is the probability of picking a brown one? So notice that the sum of all these probabilities has got to be 100%. So what we've seen already is we have 14% plus 14%, plus 20%, plus 24%. So that is stuff we know so far. What we don't know is how much do we have for the red and how much do we have for the brown? We do know that it's the same probability, so we're gonna have some value, we'll call it X and there's gonna be two X's there that we need to then solve for and figure out that probability. All right, so let's see what we have so far. So we've already accounted for the following. So we got 14 plus 14 plus 20 plus 24. That accounts for 72% of the total, like so. And so if we take that away from 100, we then have that two X is equal to 28%. So if you divide that by two, so we'll divide that by two there, you get that X is gonna be 14%. So the red M&M and the brown M&M have a probability of 14%, so we see that the correct answer would then be F.