 Hello and welcome to the session. My name is Mansi and I'm going to help you with the following question. The question here says solve each of the following equations. Fifth equation is x squared plus 3x plus 5 equal to 0. In this question we have to solve the equation x squared plus 3x plus 5 equal to 0. Now before starting the solution we see the key idea behind the question. Now we see that solution to a quadratic equation ax squared plus bx plus c equal to 0 where a is not equal to 0 is given by x equal to minus b plus minus under the root b squared minus 4ac divided by 2a. This is equal to minus b plus minus under the root 4ac minus b squared ieta divided by 2a. Now we start with a solution to this question. The equation given to us is x squared plus 3x plus 5 equal to 0. Now if we compare this equation with ax squared plus bx plus c equal to 0 we get a equal to 1, b equal to 3 and c equal to 5. We get b squared minus 4ac equal to 3 squared minus 4 into 1 into 5 that is equal to minus 11. So x becomes minus 3 plus minus under root minus 11 divided by 2 into 1. This can also be written as minus 3 plus minus root 11 ieta divided by 2. Therefore our solution to this question is minus 3 plus minus under the root 11 ieta divided by 2. I hope you understood the question and enjoyed the session. Goodbye.