 Hi and welcome to the session. I am Priyanka and let us do the following question together. It says, find the values of the trigonometric function where we are given sin minus 11 pi by 3. Let us start with our solution. Sin minus 11 pi by 3. We know that the values of sin x repeats after an interval of 2 pi. Therefore, we can write sin. Now this value can be written as 2 into 2 pi minus 11 pi by 3. This will give us the value of sin 4 pi minus 11 pi by 3 which on simplification gives us pi by 3. Now the value of sin pi by 3 as we know from our knowledge comes out to be root 3 by 2. So the answer is root 3 by 2 that is the value of sin minus 11 pi by 3. So I hope you enjoyed the session. Bye for now.