 Welcome to the session. In this session, we will discuss a question which says that with time in r's h, the distance travelled d in miles by two cars a and b are given in the form of linear functions. Distance travelled by car a is given by d is equal to 18 h and distance travelled by car b is given graphically determine which car is moving fast. Now, let us start with the solution of the given question. Now, in this question, we are given relation between time in r's and distance travelled in miles of the two cars that in different representation. For car a, the relation is represented as graphically and for car b, the relation is given graphically and we have to determine that which car is moving fast. Now, we know that speed is equal to distance travelled upon time taken or you can say speed is distance travelled per hour. So, unit height is given by slope of two linear functions. Here we will compare the two given linear functions with respect to their slopes. Now, in function 1, we are given a linear function showing a relation between m distance travelled d, the equation d is equal to 18 h is of the form y is equal to mx whose graph is a straight line passing through a region is equal to 18. It means travelling one unit is equal to one hour. Now, let us take c dash which lie on the slide. Now, we know that slope is equal to rise. Now, we know that on horizontal axis, one unit is equal to one hour run is equal to a vertical axis. One unit is equal to 10 h is equal to 1, 2 and 3 minutes. It should be equal to, so slope is equal to 30 which is equal to that car b is travelling at the rate is travelling at the rate of 80. And the rate of 50 is moving. The slope using coordinates of c and c dash has coordinates of c are 30 and coordinates slope is equal to upon change in m 30. This is equal to 30 upon 2 which is equal to equation of the given question. That's all for this session. Hope you like and enjoy the session.