 Hello and how are you all today? The question says a man borrows Rs 9,006 per annum and promises to pay off the loan in 20 annual installments beginning at the end of first year. Find the annual payment to be paid. We need to use the value of 1.06 raise to the power minus 20 as 0.3119. Now let us start the solution by writing down whatever is given to us. Here we are given V as Rs 9,000. We are given the rate of interest as 6% per annum which can also be written as 0.06 and the number of years are given to us as 20 years. We need to find the value of R. Now we know the formula for V that is R bracket 1 minus 1 plus R raise to the power minus N upon R. Now we will be substituting these three values that are known to us. It is 9,000 equal to R upon R that is 0.06. This is the rate of interest 1 minus 1 plus R that will be 1.06 raise to the power minus 20. That is further equal to 9,000 into 0.06 equal to R bracket 1 minus the value of it is given to us in the question as 0.3119 which implies we have 9,000 into 0.06 equal to R into their difference comes out to be 0.6881. So to find out the value of R we will be multiplying now 1,000 with 0.06 and dividing it by 0.6881 and after doing the calculation we have the value as rupees 784.77 as the value of R. So therefore we have the annual payment to be paid is rupees 784.77. Right so this completes the session hope you understood it well. Hey you just need to take care of your calculation do remember the formula that is to be used and have an ideal state.