 Hello and welcome to the session. I am Deepika here. Let's discuss a question. Where the following is in an AP, if they form an AP, find the common difference D and write 3 more terms. 1 square, 3 square, 5 square, 7 square and so on. Let's start the solution. Solution. The given list of numbers is 1 square, 3 square, 5 square, 7 square and so on. We have a2 minus a1 is equal to 3 square minus 1 square which is equal to 3 plus 1 into 3 minus 1. This is equal to 4 into 2 which is equal to 8. Again a3 minus a2 is equal to 5 square minus 3 square which is equal to 5 plus 3 into 5 minus 3. This is equal to 8 into 2. This is equal to 16. Hence we have seen that a k plus 1 minus a k is not the same every time that is since a2 minus a1 is not equal to a3 minus a2. Therefore the given list of numbers does not form an AP. So for the above list of numbers is no they do not form an AP. I hope the question is clear to you. Bye and have a good day.