 Hello and welcome to the session. In this session we will discuss a question which says that if a plus b iota whole square is equal to c plus d iota, then where c over a plus d over b is equal to 3a minus b square over a. Now, when we start with the solution, now it is given that a plus b iota whole square is equal to c plus d iota. This implies a square plus b square iota square plus 2a b iota is equal to c plus d iota. Now this implies a square plus b square into a iota square which is minus 1 plus 2a b iota is equal to c plus d iota. This further implies a minus b square plus 2a b iota is equal to c plus d iota. Now we know that complex number is of the form a plus b iota where a b are real numbers, the real part and b is called the imaginary part. Now here equating minus b square is equal to c and equating the imaginary part it will be a into square over a the whole is equal to c equal to d over b minus b square over a is equal to c over a is equal to d over b over b will be equal to now particular values of c over a and d over b from here will be equal to 2a which is further equating minus b square over a over b is equal to 3a minus b square over a and that's all for the session hope you all have enjoyed the session.