 Hello and welcome to this session. Let us understand the following problem today. An express take takes 1 hour less than a passenger train to travel 132 km between Mysore and Bangalore without taking into consideration the time they stop at intermediate stations. If the average speed of the express train is 11 km per hour, more than that of the passenger train, find the average speed of the two trains. Now, let us write the solution. First of all, let us write the formula that we will be using. Speed is equal to distance upon time or distance upon speed. Now, let the speed of the express train is equal to x km per hour. Therefore, speed of the slow train is equal to x minus 11 km per hour taken by is equal to distance to be 132. So, it is equal to 132 by x is equal to 132 by x minus 11. The equation form will be 132 by x minus 11 minus 132 by x is equal to 1. Now, solving this taking LCM x minus 132 into x minus 11 whole divide by x into x minus 11 is equal to 1. Which implies 132 x minus 132 x plus 1452 is equal to x square minus 11x gets cancels. So, we get x square minus 11x minus 1452 is equal to 0. Now, spitting the middle term, we get x square x minus 44x minus 1452 is equal to 0. Which implies taking x common, so we get x plus 33. Now, here taking minus 44 common, we get x plus 33 is equal to 0. So, minus 44 into x plus 33 is equal to 0. Which implies x plus 33 is equal to 0 and x minus 44 is equal to 0. Which implies x is equal to minus 33 and x is equal to 44. This is equal to minus 33 not possible. Therefore, x is equal to 44. So, kilometer per is equal to 44 minus 11 which is equal to 33 kilometer per hour. Therefore, unspeed of passenger train 3 kilometer per hour. I hope you understood the problem. Bye and have a nice day.