 Hello and welcome to the session. Let us understand the following problem today. A train travels 360 km on a uniform speed. If the speed had been 5 km per hour more, it would have taken one hour less for the same journey. Find the speed of the train and let us guide the solution. First of all, the formula which we will be using in the problem will be speed is equal to distance upon time and time is equal to distance upon speed. Now, let the speed of the train be 60 km per hour. Distance travel is given as 60 km, therefore distance upon speed which is equal to 360 by x km, it becomes x plus 5 km per hour. Therefore, time taken is equal to 360 by x plus 5. Our equation will be 360 by x plus 5 is equal to 1. This we get x into x plus 5 is equal to 1, which is equal to x divided by x is equal to 1, which implies 360x plus 1800 minus 360x is equal to x square plus 5x. x cancels, so we are left with plus 5x minus 1800 is equal to 0. 1800 is equal to 0. Now, taking common we get x plus 45 minus 40 into x plus 45 is equal to 0, which implies into x plus 45 is equal to 0, which implies x is equal to 40 and x is equal to minus 45. With negative minus 45 is not possible, which is equal to 40. Any problem, bye and have a nice day.