 Let's take a look at how to use implicit differentiation in order to find a second derivative. We're going to start out by using implicit differentiation as we typically would. So we would have 2x plus 2y dy dx equals zero. Solving that for dy dx then, we get negative 2x over 2y, which of course simplifies to negative x over y. To find the second derivative then, we need to employ the quotient rule because we have negative x over y. So using the quotient rule, we would have y times negative 1 minus, now we keep the negative x, derivative of y is going to be 1 dy dx and that's all over y squared. So if we were to just simplify this a little bit, we'd have negative y plus x. Now in place of dy dx, we're going to put the negative x over y that we had found above. So if we continue simplifying from here, let me go to the next page. We would have negative y minus x squared over y all over y squared. Now of course, we cannot leave it as a complex fraction like that. So we're going to simplify this by multiplying through by y by the little denominator that we need to eliminate. So our final answer in the end is negative y squared minus x squared over y cubed.