 One last reaction is the weighting reaction and then we take a break. No, no, no, it's different. Weighting reaction, what is the reaction of? Reaction of phosphorus, phosphorus, elides. I don't know the pronunciation but the same goes for both of them. Elides, elides, whatever it is. So this reaction is, it is actually triphenyl, triphenyl phosphonium ion. Triphenyl phosphonium is the C6H53, Pc. Carbon can be used here, though hydrogen can be used, alkyl group anything is possible. So I have written the general thing here. It is negative and this is positive. So this is the reagent we have. This negative charge because of this, this has, this behaves as a carbon ion. And in this reaction, from this reaction we can actually convert aldehyde or ketone into alkyl. Aldehyde or ketone into alkyl. Suppose the reaction is this and the reagent we are using suppose is this C6H5, P, positive. And instead of A and B I am taking hydrogen here, CH2. The product of this reaction will be this. What we need to do just to remove this double bond O and with this, so this overwrite on this whatever group we have here, CH2. Plus we will get C6H5, P, positive. This is the product we get. Double bond O, write on just whatever we have here, CR2, CH2 whatever it is, just write it down. All the reaction proceeds you see, this is a carbon ion. This attacks onto this carbon. Carbon will govern this bond goes here. Now this forms O minus CH2, P, TH3, positive. Now this O minus forms a bond with this phosphorous and it forms and then when you heat this, this comes over here, this goes here and it forms simply this double bond O is for removal here. Very specific reaction. And we get alkene from this aldehydr. Okay. What are the chapters we are left with after amine? Biomolecules. Biomolecules. Sir, leave biomolecules, polymers. So that's how we use this. Solid state. Solid state is human. Solution. Biomolecules will do. PDF. PDF will do. PDF will do. Okay. First method of preparation, write down. From greener reagent. Sir, you can take GeoC extra classes in Dresher or something. Dresher, I am not here. Many people like that. Sir. Dresher, I am going home. Dresher, you are here only, all of you? Yeah. Sajeev. You just say, okay. Okay, I will let you know. If possible, I will take this. Because I am going on 6th. Where are you going? I am going home. Patna. So I am going on 6th and then I am coming back on 13th. I will let you know. Okay. 32s, we have holiday not late. So I will let you know. GeoC, let us begin. Okay. So you see, preparation of, what did I say? Greener reagent. From greener reagent, right? Okay, write down. Greener reagent on reaction with CO2. Greener reagent on reaction with CO2. In presence of ether, in presence of ether, forms acid. So reaction is RMGX plus CO2. In the second step, we will use H plus H2. Reaction of RMGX, mostly we use H plus H2 in the second step. The product to get is RCOOH plus MGOHX. Okay. It goes like this. You see, O double bond, C double bond, O. However, in this mechanism, it is not important. I will just give you a bit of idea here. This R minus and MGX plus we have, right? R minus attacks onto this carbon. This goes here. And it forms R, C double bond O, O minus. Plus we will get MGX plus. In the next step, when we have H plus H2O, from this H2O, it gets OH. And this H plus attached over here. We will get acid RCOOH plus MGOHX. The mechanism is not important. Okay. So we are getting what you need to keep in mind here. We are getting carboxylic acid with respect to the alkyl group of krillnautriation with one more carbon atom. Okay. We are getting acid with respect to alkyl group of krillnautriation with one more carbon atom. That is what you need to keep in mind. Okay. Now in this reaction, you tell me what is the product we get. It is an RCH2X and it is heated with MG heat wave. You get A. And this reaction takes place with CO2H plus H2O. The product B is what? COH plus MGOHX. Absolutely. First of all, we get here what? NRB agent. So R. MGH2. CH2. MGH2. MGH. MGH. And this is the reaction of RMG in CO2 and acetic medium. So we will get acids with one carbon more than the number of carbon atom present in alkyl. So it will be R. CH2COOH. Okay. Acetic hydrolysis of ester. This reaction we have done. Write down acetic hydrolysis of ester. RC double bond OOR dash with H plus H2O. What is the product we get here? Alcohol plus acid. So we get what? ROH plus ROH. This reaction takes place in basic medium also. Basic medium also it is possible. OH minus H2O. We have done this reaction as an email. Okay. Same reaction. So this reaction is RC O minus OH. And we have OOR. And when it comes back this goes out as a leaving group. So it forms for RC double bond OOH plus OOR minus and then deprotonation of this. Because basic medium is O. Acids are form over name. Right. So we will get ROH plus RC O minus. Okay. We have done this reaction. Next write down oxidation of alkenes and alkynes. This also we have done in alkenes hydrocarbon chapter. Oxidation of alkenes and alkynes. The reagent used here. The reagent used here is acidified or hot alkaline K2CR207 or KMLO4. These reactions are very simple. You see if you have this reaction RC H double bond CHR dash and when it is heated with acidified K2CR207. Four desintoxysate that combines here it forms. This double bond you have to break and write here COOH and COOH. So product will be RC OOH plus R dash COOH. There is no mechanism of this reaction. Just give it to know how to write on the product. Double bond you need to break. COOH here, COOH here. Sir we are given a compound with multiple double bonds. Multiple double bond. Different types of carboxylt acids. No multiple double bond we won't go by this method because for that we require a very high temperature to break all the double bonds. It's not like three double bond so sorry two K acid bond. For that very high energy we need. For that there are several methods. Generally we use here only one unsaturation double bond or triple bond. Like you see this reaction if you have this other cyclic compound or cyclohexene. And it's the reaction with same reagent. So what we get this bond breaks. What we get here? C double bond C double bond OOH and here we have COOH double bond OOH. Same kind of reaction we have with alkyne also. Next point to write down. We can also use ojonite with H2O. This is also another reagent we have. Ojonite with saroxide. So you see the similar kind of reaction RC triple bond CR dash with O3 H2O2. It gives RC OOH plus again R dash COOH. Triple bond we need to break. C double bond OOH. One note you write down. Ojonite we use O3 with ZN H2O and there we get aldehyde or ketone as the product. This is oxidation. That's why we are using peroxy acid. Oxidation reaction. Write down when a mixture of alkyne, when a mixture of alkyne, carbon monoxide and water in the steam form. Water actually in regular steam. When a mixture of alkyne, carbon monoxide and water heated in presence of H3PO4. Monocarboxylic acid forms. Monocarboxylic acid forms. So this reaction you see. Write down this reaction we call it as coach reaction. KOCH. This reaction is coach reaction. H2C double bond CH2 with CO H2O with H3PO4. Acidic medium it is. Product here is CS3 CH2 COOH. See we are getting higher acid into this. One carbon is more here with respect to this. When you have this molecule CH3CH double bond CH2, unsymmetrical alkyne we are taking. Plus CO H2O steam with H3PO4. The product will be CS3 COOH CS. This is the product we get. Monocarboxylic acid. You can understand this. Medium is acidic. So we have H plus. Right. So H plus. This will take this H plus. And we get CS3 CH positive charge CS3. And with this carbon monoxide C double bond O with one lone pair onto this carbon. Two lone pair onto this oxygen. This attacks onto this positive charge carbon. Again for this also mechanism is not important. So it is CS3 CH CS3. And here we have C double bond O positive charge. Like because it donates its lone pair of link. Now from this H2O OH minus attacks onto this. And it forms CS3 CH COOH.