 अड़ा इद फ्रेंज तो आज हम लोग कोर्योलिस फोर्स के बात करेंगे और ये जो फोर्स है दोसको ये इतना विजिबली इस तरह से कीर नहीं होता है हो नहीं लुक, कहा से आदे ही? तो इस्ले हम लोग को अज आप यहां पे अटेंचन देनी के जरोत है, की ये कब लगता है, और किस तरह से हम इस को अखाँउंट में लेते हैं? और चलिया दोसको इसके बारे में हम लोग बाख कर तेंगे रहुं. तो आपको अपको एक सिटूइशन दूमा जिस में हम लोग खुड़ा सा दिसकशन करेंगी असके बारे में. तो समझ लिजे की जैसे आपके पास एक रोड है, और ये रोड इस अच्सिस के बाओड रोटेट कर रही है, with a certain angular velocity. और मा लिजे यस रोड पे एक स्लाझर है, और जैसे यस रोड रोटेट होग है, मा लिजे रोड यहां पोझछी, रोटेट होंगे, the slider will reach here. तो यस में आपको कोन कोंसे आपको हखेरशियं यहाँ पुरे समझ में आँ आया तो एक ऐक सकर तो आप बडवदे आसाणी से बता सकते हैंस की यहाँ पर एकन स्ह सेन्तरि पितल ठ्यल आख्रिश्यन लग्रा होगा यहाँ अमेगा श्चौर अर जब देलीग. अप क्या इसके लावा कोई आपको समझ में आरा है, विस्वली तना क्यर नहीं है, लिकन अगर आप द्यान से यहाँ पर देखेंगे चीजें, तो आप पाएंगे कि दोस तो यहाँ पर मालीजे ये आर्वन रेडियस है, और यहाँ पे मालीजे ये जब अब अबजेक वहां � यहाँ यहाँ आप दो तंजेएंछल रोस्टी होगी डोस ठो खो लोगी आर्वन औंचएं, अग informação यहाँ पे थंजजेंचल बलोस्टी होगी डोस गो. वहाँ पे थंजेंचल लोस्टी होगी एदो अभी होगी. अब देखेगा कि जो अब देखेगा एब देखेगा, तो है नी आदे ग्धका۔ है olurs अड़ने ऎदे विल्तो हैश鴌र कोँउइ ञादलubscribe mecano haith tamb distortion to se這樣. यो टेनकेंजल लोसति 150 bh workshopamerokolpe markersov ये चाम ministre तुह की में से मोग माअःःए। आप भी में ऐसप से विलए जो जैश में लोसा है। और करे गे लीखस exhibition यहाँ पर एक गलोशी चेंज होगी, लेकिन यहाँ पर आपको ये बी देगना पड़ेगा खी जो गलोशी तेंजंचल डरेक्छ्म आप यह भी चेंज वो रही है तो एस की वजे से जब इसने अपना रेडिएश चेंज किया जो तेंजंचल डरेक्च्म बगलोशी चेंच र के ऽहद लिग़ी कि कोरलिश फुर्ष उस सिनारेंने लखता है, जभ एक आबजेड रोटेट रहा है, और उस आबजेड ड़। गे वो भर आवभद आप माल लिजे अपना गदेजा अफ़ी में आपना रहा गरदेट आपता है एज़े लोग यह दिस ज़ा रब अपना ट ये एर्थ है कि ये टिःट के अगर रोटेट करा है दोस्तो वया उन्टी जे यहा पर हूँ वया अगर यहाँ से तर्वल कर गे ये पूँट पे पूँचा मेरी जो तेंजंचर लोस्ती यह तो वयों चेंज फोँरी है because of the earth's rotation I am getting closer to the axis of rotation so in the same way this scenario is also there alright so I will go into more detail I will show you a visual representation which will make it clearer now see here the position of the rod is shown here the rod was in position 1 and as the rod is changing its position this slider is moving forward so as the slider was near the axis of rotation its tangential loss was less in the second movement its tangential loss increased so this is how its tangential loss increased so definitely there is a force in the tangential direction and that force is Coralis force but if you want to understand this rotating frame of reference assume that the observer of the rod is rotating with the rod if you are rotating with the rod then only this slider will look radially outward so due to Coralis force or Coralis force you will not be able to see the acceleration so you will have to understand that not only you will have to apply a centrifugal force M omega square R along with that you will have to consider a Coralis force alright so we have understood that Coralis force will apply and its direction will be tangential alright its direction will be tangential so the magnitude of this Coralis force to know this let's study the mathematical alright let me tell you one more thing this Coralis force is nothing but normal reaction between the rod and the slider due to that Coralis force you can experience friction let's assume that the coefficient of friction is mu so mu times Coralis force will be the friction along the rod alright so this is what we have understood conceptually let's see what is its expression and its value so you can assume that this is your rod this is your rod this rod is rotating alright and with angularity omega is rotating and the slider was already here now the slider has reached here alright and this distance friends this distance you take R1 and this distance you consider R2 this is R1 and this is R2 alright now here one thing you have to pay attention to that we are talking about instantaneous attrition so when we are discussing about instantaneous attrition then we will have to assume that the angle of rotation is very small now that delta t is tending to zero so this angle theta is close to zero now here tangential velocity R1 omega and here tangential velocity R2 omega R2 omega is a little bit more so the vector length of this I will make it a little bigger alright so this velocity friends this is R1 omega and this velocity is R2 omega alright now if delta theta is very small then our diagram will look like this this length you can assume it is delta r delta r which is R2 minus R1 alright and this velocity is point number 2 on my R2 omega point number 1 velocity will be less I will take R1 omega this is R2 omega and this is R1 omega so my change in velocity friends my change in velocity that difference in the length of the vector because delta theta is so small that R1 omega and R2 omega will look like parallel vector so this length this length which is my change in velocity that will be R2 omega minus R1 omega alright so I can write this R2 minus R1 times omega and R2 minus R1 we write delta r delta r into omega now here the radial velocity when this slider is going forward so at any moment instantaneously assume its velocity is v so delta r because it is very small I can say that delta r velocity into delta t although velocity can be changed but my change in time the amount of time I am taking it is very minuscule so delta v the change in velocity delta r I can write radial velocity into delta t the radial velocity is velocity at that moment when I am trying to get the value of corollus force so delta v is your v r delta t into omega from here delta v by delta t our radial velocity into omega alright so this change in velocity per unit time first of all this is acceleration and the direction of this acceleration is towards the direction of changing velocity which is tangential so this is a tangential acceleration as we can say now here you have to think about one more thing friends here our acceleration is coming because of tangential velocity our acceleration the radial velocity is sliding along the rod because of it so how much it is and in which direction it is let's take a look so you can assume that this vector because my delta t is very small so my radial velocity is almost constant so angle is small and radial velocity is also not changing so my radial velocity was along the rod was going horizontally so v r is like this now my v r is tilted and this angle you can assume that when this radial velocity direction change because of this change in direction there is an acceleration and how will you take that out you simply have to take out this vector this vector minus that vector although magnitude is equal to radial velocity because the amount of time is small but the direction has changed so because of that this is your delta v radial is ahead and you will see that the direction of change in velocity is perpendicular to the radial velocity because it is a tangential direction alright so one equation will come because of this so how will you write take this tangential equation one second expression for tangential expression you will write delta v r divided by delta t alright now you have to take out delta v r so friends you will see one thing that the delta theta the way we define the angle you will know that the angle the arc length the magnitude of delta v divided by the radial velocity this way we can write alright so delta v r our numerator we can write delta theta into v r and in the denominator delta t alright so clear cut friends the second term of tangential equation comes from delta theta by delta t omega omega into v r so you will see that because the slider is changing the radius of the revolution because of that there are two tangential equations one because the tangential velocity is changing and the other because the radial velocity is changing the direction the total equation will be sum of these two and that equation because of the corollist force that is the equation so here I will summarize the space friends the acceleration of corollist force will come in both the sum because the direction is the same both the sum is 2 times radial velocity into angular velocity so how much the corollist force will be corollist force will be corollist acceleration so 2 m v r into omega alright friends this is the summary of corollist force now in the next video we will bring some questions in which corollist force is being used in fact in j-advance in few few times in fact in j-advance they ask you questions on the corollist force but keep in mind this corollist force will only be used when some object is rotating and in that rotating object some second object is changing its radius while traveling on the rotating object itself but if the radius is fixed and object is rotating then no corollist force will be used because you will see that the radial velocity will become 0 so radial velocity is very important alright so in this way you can take care of corollist force in the next video we will bring some questions in which this concept becomes more solid alright so thanks for watching the video