 Hello and welcome to the session. In this session, we will discuss the following question and the question says that one, look p the subject of the formula i is equal to p into r into t upon 100. That two, look d the subject of the formula s is equal to m upon 2 into 2a plus n minus 1 the whole into d the whole. Before we start solving the question, let us first recall that is subject of a formula. Subject of a formula is a variable that is expressed in terms of other variables. So this is the key idea for this question and using this key idea, we will solve the question. Let's start the solution now. In the first part, we are given this formula and we have to make p the subject of the formula. So for part one, the given formula is i is equal to p into i into t upon 100. We have to make p the subject of the formula. Going back to the key idea, we have subject of a formula is a variable that is expressed in terms of other variables. Where i is the subject of the formula as it is expressed in terms of other variables that is p, r and t. So now we will write p in terms of other variables that is i, r and t. So we will express p in terms of other variables. For this, we will keep p on one side of the equality and transpose the other terms on the other side of the equality. This implies p is equal to i into 100 upon r into t. So in this formula, p is the subject of the formula. Hence the required formula with subject p is equal to i into 100 upon r into t. This is the final answer for part one. Now in part two, we are given this formula and we have to make d the subject of the formula. So part two is s is equal to n upon 2 into 2a plus n minus 1 the whole into d the whole. Now we will open the brackets. So this implies s is equal to ma 2 and 2 get cancelled plus n upon 2 into n minus 1 the whole into d. Now we have to make d the subject of the formula. So we will transpose all the other terms on the other side of the equality. This implies s minus ma is equal to n upon 2 into n minus 1 the whole into d. This implies 2 into s minus ma the whole upon n into n minus 1 the whole is equal to d. So in this way, we have expressed d in terms of the other variables. So d is the subject of the formula in this formula. Hence the required formula with subject d, d is equal to 2 into s minus ma the whole upon n into n minus 1 the whole and this is the final answer for part two with this the end our session. Hope you enjoyed the session.