 Hello and welcome to the session. In this session we will discuss the following question and the question says, construct a right angle to triangle PQR in which angle Q is equal to 90 degrees, QR is equal to 7 centimeters, PQ is equal to 4 centimeters. So we have to construct the right angle to triangle in which the sides forming the right angle are given to us. Let's start the solution now. We are given that QR is equal to 7 centimeters. First we shall construct QR. Step one of construction is draw a line segment QR which is equal to 7 centimeters. So we have drawn this line segment QR of length 7 centimeters. We are also given that angle Q is equal to 90 degrees. So now we shall construct an angle of 90 degrees at Q. Step two of construction is at Q construct angle AQR which is equal to 90 degrees. So we will now construct an angle of 90 degrees at Q. For this we first draw an arc with center at Q and any radius. Now we will bisect this arc since this angle is of 180 degrees. Therefore the angle formed by bisecting this angle is equal to 90 degrees. Thus we have angle AQR is equal to 90 degrees. It is also given to us that PQ is equal to 4 centimeters. So we shall construct the side PQ in the third step. Step three is with QS center and radius equal to 4 centimeters draw an arc to cut AQ at P. So with QS center and radius equal to 4 centimeters we draw this arc and the point where this arc cuts AQ is the point P. Step four is join PR. So we will now join the points P and R. Thus we have constructed triangle PQR in which QR is equal to 7 centimeters, PQ is equal to 4 centimeters and angle Q is equal to 90 degrees. Therefore triangle PQR is the required triangle. With this we end our session. Hope you enjoyed the session.