 Hi and welcome to the session. I am Arsha and I shall be helping you with the following question that says insert 5 numbers between 8 and 26 such that the resulting sequence is an AP. So let's start with the solution and let the 5 numbers inserted between 8 and 26 be A2, A3, A4, A5 and A6. So the AP which is formed is 8, A2, A3, A4, A5, A6 and 26. So clearly this is the first term and this is the 7th term of the AP. Now the 7th term of the AP is A1 plus 7 minus 1 into D and the 7th term is 26. First term is 8 plus 6D. So this implies that 26 minus 8 is equal to 60 or 18 is equal to 60 so this implies D is equal to 3. Now let us find the numbers which are inserted between 8 and 26 one by one. So the first number is A2. It is formalized A1 plus 2 minus 1 into D. So 8 plus D that is 3 is equal to 11. Now let us find A3. So A3 is A1 plus 3 minus 1 into D. So this is 8 plus 3 into 2 since 3 minus 1 is 2 so this is equal to 8 plus 6 which is equal to 14. Now let us find A4 that is formalized A1 plus 4 minus 1 into D. So this is equal to 8 plus 3 into D is 3. So 8 plus 9 this is equal to 17 and now let us find A5 is A1 plus 5 minus 1 into D. So 8 plus 4 into 3 so we have 8 plus 12 this is equal to 20 and now let us find the last number which is A6. So we have A1 plus 6 minus 1 into D so we have 8 plus 5 into 3 this is equal to 8 plus 15 this is equal to 23. 5 numbers inserted between 8 and 26, 14, 11, 14, 17, 20 and 23. So this completes the session take care and have a good day.