 Hi and welcome to the session. Let us learn the construction of a triangle when the measures of two of its angles and the length of the side included between them is given. That is ASA criteria. Let us construct a triangle AVC in which VC is given to be 5.3 centimeters, angle V is equal to 45 degrees and angle A is equal to 75 degrees. First of all let us draw the rough sketch of triangle ABC. So here we have a rough sketch of triangle ABC. Now let us mark the measurements given over here. We have given that BC is equal to 5.3 centimeters, angle B is equal to 45 degrees and angle A is equal to 75 degrees. Now here we want to construct a triangle in which the measurement of two angles and the side included between them is given. Here we are given the side BC. So we must have angle B and angle C. That means we need to find the measure of angle C. Here we are given the measure of angle A and angle B. So by angles some property of a triangle we have angle A plus angle B plus angle C is equal to 180 degrees because some of all the angles of a triangle are 180 degrees. Now substituting the values we get angle A is 75 degrees plus angle B that is 45 degrees plus angle C is equal to 180 degrees. That means angle C is equal to 180 degrees minus 75 degrees minus 45 degrees which is equal to 60 degrees. That means angle C is equal to 60 degrees. Now let us construct the triangle ABC. So first of all let us draw a line segment BC of length 5.3 centimeters. So here we have drawn the line segment BC of length 5.3 centimeters. Our first step of construction will be draw a line segment BC of length 5.3 centimeters. Now we have angle B is equal to 45 degrees. So here at point B we will construct an angle XBC equal to 45 degrees. So here we have angle XBC equal to 45 degrees. So our second step of construction at point B draw angle XBC equal to 45 degrees. Similarly we have angle C equal to 60 degrees. So at point C let us draw an angle YCB equal to 60 degrees. So here we have angle YCB equal to 60 degrees. So as third step of construction at point C draw angle YCB equal to 60 degrees. Now from the rough sketch we can conclude that the point A must lie on the ray BX and also it must lie on the ray CY. So that means point A will be the point of intersection of ray BX and CY. So here we have point A that means point of intersection of BX and CY is point A. So we got the triangle ABC. Thus triangle ABC is the required triangle. So here we have constructed the triangle in which the measures of two angles and the site between them is given. With this we finish this session. Hope you have still understood the construction. Goodbye, take care and have a nice day.