 Hello Myself, Mr Satish Thalange, Assistant Professor, Department of Civil Engineering, Walsh and Institute of Technology, Solapu. In today's session we are going to see regarding the example of project network crashing or you can say compression. At the end of the session, the particular learner will be able to determine the optimum time as well as optimum cost associated with the particular project which is going to help you to make a decision regarding the project scheduling. Here the total project cost is nothing else, it is a particular summation of direct cost as well as indirect cost. And a crashing of network or you can say crashing of activity is nothing else, a reduction of the time or duration of the particular activity, optimum cost of the particular activity or you can say overall project. Here we are interested to crash the particular activity or you can say reduce the duration of the activity to minimize the overall project duration by considering the optimum cost also. This is a particular project in which we are observing that there are the four activities with their normal duration as well as normal cost, crash duration as well as crash cost. And the indirect cost associated with the particular project is 2000 per week. This is a normal network diagram construction of a particular project which is showing that the particular project critical path is 1, 2, 3 and 4 and the overall project duration of is 13 weeks. And this is a table which is showing the floats of respective activities or you can say individual activities. Now, this is a slide which is showing you the particular cost loop of its respective activity. When we observe all these four activities, the particular values of each activities are being determined which is showing that 4000 is the cost loop of the first activity and as follows. Now, this is the first step which is showing you that this is the time scale diagram of normal network diagram. Here the normal network diagram or you can say a non-scale network diagram is now represented by the scalar representation which is called as time scale diagram. We take a baseline as a baseline as a critical path and left activities are represented above in the below the baseline. Now, the overall total project duration is nothing else it is a 13 weeks and the total normal direct cost of the project is a summation of all the normal cost of the particular activity. In this table, this is a normal duration and the cost associated with the normal durations are overall 4000, 3000, 3600 and 5000. Summation of this we get the 15600 and the total indirect cost of the project is equal to project duration multiplied by indirect cost per week that is 13 multiplied by 2000 that is 26000. So in the initial stage without crashing the overall total project cost is nothing else it is summation of total direct cost plus total indirect cost it is a 41600. Now let's start to crash the activities. Now we have to observe the table here I have shown you that this is a activities it is that and the second column is representing the delta T which is showing that we can compress this practical respect to activity by 2 weeks, 3 weeks and 2 weeks and 2 weeks and their cost slope of each respective activities are represented in this particular column. Now let's start to observe. The first observation when I observe this particular cost slope table or I can say the table which is showing the activities the delta T and as well as cost slope we are observing that 1200 is a minimum cost slope of activity 24 but this 24 activity is a non-critical activity. So I will go for the second cost slope minimum second minimum cost slope that is 1500 and it is related to 23 activity yes this is a 23 activity. When I observe this 23 activity the parallel activity is 24. So my option first if I compress activity 23 by 2 weeks then the extra cost will be 3000 plus 2 which is equal to 3000 rupees means if I compress activity 23 the extra cost that is direct extra cost will be 3000 because when we are going to compress the activity means what we are going to complete the activity with the faster. So to get the complete with minimum duration we have to assign the more resource then the more resource then extra cost. So this is table which is showing you that activity 23 is being compressed by 2 weeks and its extra cost is 3000. But activity 24 it is shown as it is 0 because here 24 activity is having the float of 2 as we see in the this particular table sorry here 24 is having the float of 2. So if I compress it by 2 weeks so it won't consume any extra cost so it is 0 into 1200 it is 0. So the summation of this we get 3000 means if I compress activity 23 activity by 2 weeks the extra cost is 3000 that is first option. Second option I can say second option or second observation in second option after 23 activity that is after 1500 the next minimum is particular like is the 2500. When I observe which is of activity 34 when I observe 34 activity again the pile activity is 24 only. So if I compress 234 activity by 2 weeks then the extra cost will be 5000 because activity 34 if I compress by 2 a 2 into 2500 it is a particular 5000 actually it should be 5000. So finally when I observe the option 1 and observed option 2 the 3000 is good as compared to the option 2 that is 5000. So compression of activity 23 by 2 weeks which adds extra cost of 3000 only. So I will go with that compression of activity 23. Now after compression we should determine what is the overall duration of the practical project and the overall total project cost. So the duration of the particular project is now 11 and now the total normal direct cost is equal to summation of overall normal cost plus additional extra cost. This 15600 plus 3000 that is a 18600 because in first step when we observed here the normal direct cost was first step without compression it was 15600 we have to take as it is plus additional cost because we have compressed the activity 23 that additional cost is 3000 so 18600 and the total indirect cost of the project is nothing else it is equal to project duration multiplied by indirect cost of indirect cost per week. So 11 multiplied by 2000 that is 22000. So total project cost is equal to total normal direct cost of project plus total indirect cost of the project that is the summation of A plus B we are getting 40600. Now this is newly obtained time scale diagram of the project duration 11. Now let's move towards the next step with help of this time scale diagram we have to compress once again in the third step we are going to compress again let's see because in when we are observed the first step we are getting 41600 now the project duration and as well as is reduced as well as the project cost is been reduced that is 40600. Now let's see let's try to compress once again whether the let's after compression whether the cost is same or it is increased let's see again when I observed the particular activity 23 activity its cost loop is 1500 same here I will go for the first option if I compress activity 23 activity by one way the extra cost will be of now 2700 that is how which is when we present in this table when I here when I observed 23 activity by compression again the activity 24 is parallel but now when here in the present time scale diagram we are observing that 23 activity is not having the flow because it is already consumed in the earlier step so the second option is what when we observe with the second option if I compress activity through to 34 activity by one week then the extra cost is of 4000 see when out of these two activities or you can say two options the first option is adding the extra cost of 2700 and second option is adding extra cost of 4000 so I finalize to go with to compress the activity 23 by one week which is adding the extra cost of only 2700 and now we have to determine the overall total project duration that is 10 weeks only because we have reduced it by one week so it from the level it will reduce to 10 so the total normal direct cost of the project is 1800 18600 plus 2700 is equal to 21300 and the total indirect cost of the project is nothing else project duration as it is been reduced by one week now the project is of 10 weeks so 10 into 2000 that is 2000 the summation of these two we get the overall project cost but where here we are observing that total project cost is equal to a particular 41300 so this is a table which is showing you that the total direct cost indirect cost and total project cost we are here we are observing that on the overall project duration of 13 weeks the total project cost was 41600 on the level it was 40600 but when we compress to the 10 it is now 41300 means here it has been increased so finally I declare that the optimum duration and the optimum cost of the project is nothing else it's 11 week and the cost is of 40600 this is a graphical representation of the overall total project cost as well as direct cost and indirect cost here it is a point where we are observing that it is having the minimum total project cost and these are the lines of a direct cost as well as the indirect cost and the duration of the project is 11 these are the references for the today's session thank you