 Now let's see few more set of questions. That's good. Minus 2 by x is 2t dt. 2 2 can go. Second step is not an x cube. Second step is not an x cube. Second step is x cube. Second step is x cube into x. Second step is x cube into x. So x... So let us start with basic things in terms of t. So dx by x cube is minus t dt. So minus dt is t dt. This term is t. So we know t. This term will become log t plus 2 log t. So ultimate times t square log t. Is this correct? Yeah, this is 2 log t. Please finish it off for me. Who is very big in this class today? I am related. Can you generate the sign for me? I am related. I am related. It's square letter. This is a K-curve. Which one? I am not a K-curve. I am just a K-curve. This is K-curve. I am a K-curve. I know this technique. I know this technique. I take sign to K-curve. I am not a K-curve. I am a K-curve. I am going into a So just to complete the problem. So it will be log t into t cube by 3 minus 1 by t into t cube by 3 d. So it will minus 2 log t minus t square d cube by 19. So, 1 by 9 t cube. So, your final answer is going to be minus 2 log t, t cube will be 1 plus 1 by x square to the power of 3 by d cube. So, minus d t, this term is t, this term is log t square, but approaches correct whatever you are getting. But, within the log it does not make sense, and in outside it would have a total difference, okay. If you see this term cos 2 theta, it is somehow, each of these terms have, if you do that, so 2 cos 2 theta d theta is your, so cos of 2 theta is gt by 2. So, can I say it will be half of half which is 1 fourth log, so see cos 2 minus x.