 Hi and welcome to our session. I'm Kanika and I'm going to help you to solve the following question. The question says differentiate the functions given in exercises 1 to 15 with respect to x. Sign log x. In this question we have to find the derivative of a function of a function. We can find the derivative of a function of a function by using the chain rule of differentiation. Let's first understand that what does the chain rule of differentiation mean? If y is a function of t that is y is equal to f of t and t is a function of x that is t is equal to g of x where and g are differentiable functions y is equal to f of g x y becomes a function of x in order to find the derivative of y with respect to x that means that is dy by dx we have to first find the derivative of y with respect to t and then we have to find the derivative of t with respect to x. The product of these two derivatives gives us the derivative of y with respect to x that is dy by dx and this rule is known as chain rule of differentiation. With the help of this rule we will solve this question so always remember this rule. Let's now begin with the solution. Let y is equal to sin log x with a given function. Now put log x as t so that y is equal to sin t t is equal to log x. Now we will find the derivative of y with respect to t that means we will find dy by dt. Now dy by dt is equal to cos t and now we will find the derivative of t with respect to x that is we will find dt upon dx. dt upon dx is equal to 1 by x by the chain rule of differentiation. We know that dy by dx is equal to dy by dt into dt upon dx. Now dy by dt is equal to cos t and dt upon dx is equal to 1 by x and t is equal to log x so we have cos log x upon x. So derivative of sin log x is cos log x upon x. This is our required answer. So this completes the session I and take care.