 to the session. I'll help you with the following question. The question says, the cost of 2KG of apples and 1KG of grapes on a day was found to be Rs.160. After a month, the cost of 4KG of apples and 2KG of grapes is Rs.300. Represent the situation algebraically and geometrically. If we know that a pair of linear equations, variables x and y, will be represented algebraically as b1y plus c1 equal to 0 and a2x plus b2y plus c2 is equal to 0. And geometrically, we present straight lines. Key idea to be used for this question. Let's move on to the solution. Let the cost of 1KG of apples be equal to Rs.x and also let the cost of 1KG of grapes be equal to Rs.y. According to the question, we have that 2KG of apples and 1KG of grapes on a day was found to be Rs.160. So, we have that is the cost of 2KG of apples plus the cost of 1KG of grapes that is y is equal to Rs.160 or we can say 2x plus y is equal to 160. Let this be equation 1. Again in the question we have that after a month, the cost of 4KG of apples and 2KG of grapes is Rs.300. So, we get according to the question we have 4x plus 2y is equal to Rs.300 or we can say 4x plus 2y is equal to 300. Let this be equation number 2. Thus, the situation is represented algebraically as 2x plus y is equal to 160 and 4x plus 2y is equal to 300. Consider the equation 2x plus y is equal to 160. Now, we shall find at least two solutions for this equation. If we put x as 80 in this equation, we get y as 0 and when x is taken as 30 then we get y as 100. So, the two points that we get for this equation is point A with coordinates 80 comma 0, point B with coordinates 30 comma 100. Now, let's consider the equation 4x plus 2y equal to 300. If we put x as 20 in this equation, we get y as 110 and when x is taken as 40 and the value of y is 70. So, the two points that we get here are point C with coordinates 20 comma 110 and point D with coordinates 40 comma 70. Now, we shall plot these four points on the graph. On this graph, we have taken scale on x axis as 1 centimeter and the scale on y axis is taken as 1 centimeter equal to 20 units. First, let's plot the point A with coordinates 80 comma 0. This point represents the point A with coordinates 80 comma 0. Next, we have the point B with coordinates 30 comma 100. This point corresponds to the point B with coordinates 30 comma 100. Now, we shall join the points A and the point B. As you can see on joining the point A and point B, we get a straight line. This straight line represents the equation 2x plus y equal to 160. Now, we plot the point C with coordinates 20 comma 110. This point corresponds to the point C with coordinates 20 comma 110. Then, we have the point D with coordinates 40 comma 70. This point corresponds to the point D with coordinates 40 comma 70. Now, we shall join the point C and D. As you can see on joining the point C and D, we get a straight line. This straight line represents the equation 4x plus 2y equal to 300. So, we get two parallel lines. Thus, we say the lines and CD are parallel lines. So, this is the geometrical representation of the situation. Hence, the final answer is algebraically the two situations can be represented as follows. 2x plus y equal to 160, 4x plus 2y equal to 300, where x and y are respectively the prizes in rupees per kg of apples and grapes. So, hope you enjoyed the session. Have a good day.