 Hello and welcome to the session. I am Deepika here. Let's discuss the question. Differentiate the following function with respect to X. Under root of X minus 1 into X minus 2 upon X minus 3 X minus 4 into X minus 5. So let's start the solution. Solution, let Y is equal to under root of X minus 1 X minus 2 upon X minus 3 into X minus 4 into X minus 5. Taking log both sides we get log Y is equal to 1 by 2 minus 1 into X minus 2 upon X minus 3 X minus 4 into X minus 5. So this is equal to log Y is equal to 1 by 2. Now log M over N is log M minus log N. So this is equal to log X minus 1 X minus 2 minus log X minus 3 X minus 4 into X minus 5. Again this is equal to, now log MN is equal to log M plus log N. So this is equal to 1 by 2 log Y is equal to 1 by 2 into log X minus 1 plus log X minus 2 minus log X minus 3 minus log X minus 4 minus log X minus 5. Now differentiating both sides with respect to X we get 1 over Y into dy by dx is equal to 1 by 2 into log X minus 1 1 over X minus 1 plus derivative of log X minus 2 is 1 over X minus 2 minus 1 over X minus 3 minus 1 over X minus 4 minus 1 over X minus 5. For dy by dx is equal to 1 by 2 into Y 1 over X minus 1 plus 1 over X minus 2 minus 1 over X minus 3 minus 1 over X minus 4 minus 1 over X minus 5. So substitute the value of Y here we get dy by dx is equal to 1 by 2 into under root of X minus 1 X minus 2 upon X minus 3 X minus 4 X minus 5 into 1 over X minus 1 plus 1 over X minus 2 plus minus 1 over X minus 3 minus 1 over X minus 4 minus 1 over X minus 5. Hence the differentiation of the given function is 1 by 2 into under root of X minus 1 X minus 2 upon X minus 3 into X minus 4 into X minus 5 into 1 over X minus 1 plus 1 over X minus 2 minus 1 over X minus 3 minus 1 over X minus 4 minus 1 over X minus 5. So this is our answer. I hope the question is clear to you. Bye and have a nice day.