 Hi and welcome to the session. Today we will discuss the following question. The question says draw a rhombus whose diagonals are 5.2 cm and 6.4 cm long. So let's see its solution. Here only two measurements are given that is the two diagonals but even then we can draw this figure with the help of its properties. So let us draw the rough sketch of the rhombus which will help us in visualizing the figure. So here we have a rhombus and let us name it as A, B, C. In the question we are given that the two diagonals are 5.2 cm and 6.4 cm long. So let's take AC as 5.2 cm and VD as 6.4 cm. Let us mark the intersection point of VD and AC as O. Now we know that the diagonals of rhombus are perpendicular to each other. So that means all these angles are right angles. So the diagonals bisect each other. So AC bisects VD and that implies OB is equal to OB is equal to half of VD. Therefore OB is equal to 3.2 cm. Also OB is equal to 3.2 cm. First of all let us draw AC is equal to 5.2 cm. Alright so here we have AC is equal to 5.2 cm. Let us write steps of construction side by side of construction is equal to 5.2 cm. Now that VD is perpendicular bisector of AC. So let's draw the perpendicular bisector of AC more than half of AC and draw two arcs one above AC and another below AC. Like this the composite point C with the same radius draw two arcs one above AC another join these two points as the perpendicular bisector of AC. So let's write a second step of construction 3.2 cm. We will draw an arc. So here we have made the arc and let's mark this point as construction that is with OS so 3.2 cm. So we will take OS center and radius 3.2 cm. We will draw an arc AB, BC, CD and so we got the required numbers. If you must have understood the question goodbye and take care.