 Hi, and welcome to our session. Let us discuss the following question. The question says, integrate the following functions. Given function is 1 by cos x plus a into cos x plus b. Let's now begin the distribution. We have to integrate the function 1 by cos x plus a into cos x plus b with respect to x. This can be written as 1 by sine a minus b into integral sine x plus a minus x plus b upon cos x plus a into cos x plus b dx. We have first multiplied the numerator and denominator by sine a minus b. And then we have adder and subtracted x in a minus b. Now by using formula of sine a minus b, this is equal to 1 by sine a minus b into integral sine x plus a into cos x plus b minus cos x plus a into sine x plus b dx by cos x plus a into cos x plus b equal to 1 by sine a minus b into integral. Now separate both these terms. So we have sine x plus a into cos x plus b by cos x plus a into cos x plus b dx minus integral cos x plus a into cos x plus b dx by cos x plus a into cos x plus b dx. This is equal to 1 by sine a minus b into integral sine x plus a dx minus integral tan x plus b dx. And this is equal to 1 by sine a minus b into minus log mod cos x plus a minus minus log mod cos x plus b plus c. Now this is equal to 1 by sine a minus b into log mod cos x plus b minus log mod cos x plus a plus c. And this is equal to 1 by sine a minus b log mod cos x plus b by cos x plus a plus c. And the required answer is 1 by sine a minus b into log mod cos x plus b by cos x plus a plus c. So this completes the session. Bye and take care.