 This one says 335 milliliters of water is added to 75.3 mils of a 2.07 molar calcium chloride solution. What is the new molarity of the solution? Okay, so let's write down the given information so it tells us that that the original volume of the solution was 75.3 mils and it tells us the original molarity of the solution is 07 molar and it indirectly actually tells us what the new volume of the solution is too because it tells us that the volume of water that was added is 335 mils of water Okay, so what would be the how we calculate if you need a formula for everything right? It would be V2 equals V1 plus VH2O right? Everybody okay with that? 75.3 mils plus 335 410.3 and of course actually Six figs are going to cut off there. Okay, so we'll keep that in mind for later So how do we figure out well, what's the new molarity right well you guys remember the formula? What is it? Yeah So isolate that variable So Normally we would like these in liters these volume units, but since they're both in milliliters We don't have to worry about them because they'll cancel each other out So again if these units are in the same unit you can just cancel them So molarity 1 2175.3 mils divided by V2 410.3 Mills and again, that's really to three sig figs there But those two are the three sig figs so it'll work out So 2.07 times 75.3 divided by 410.3 So If we solve this to three sig figs we get 0.3 8 0 Molar is the new Concentration of calcium chloride When we add that 335 mils of water and if you want to kind of double-check yourself just to make sure right you would expect it to become more Delude when you add just your solvent right and so we went from a very concentrated solution at 2.07 mol or 2 a much more diluted solution at point three eight zero There any questions about that? Okay