What about this one?No conjugation here we have, but this ring is not in conjugation.So aromanticin is only for ring, cyclic, planar, ring of all, conjugated ring.But this one?YesHow many pi electrons we have here?See this lone pair can form a pi bond because the vacant orbiters can donate into the vacant orbiters.We have three pi bond here, so it is 6 pi electrons and it is aromatic.This compound we call it as inorganic benzene.Formalize B3 and 3 at 6.We also call it as borazone.What about this molecule?246,and it is in conjugation.So it is 6 pi electron,aromatic.What about this one?2468,anti-aromatic.But this one is not anti-aromatic.This one is non-aromatic.Let me show you.See,whenever the cyclic compound has 7 or more atom present,7 or more atom present,then it cannot be anti-aromatic.Aromatic possible,anti-aromatic is not possible.Because anti-aromatic compounds are highly unstable compounds.So in case of this case,the molecule changes its plane and becomes non-aromatic.If the ring has 7 or more atom present,then aromatic is possible.Like you see,to 1,2,3,4,5,6,7 component,aromatic 5.But anti-aromatic is not possible.Because it is highly unstable.This molecule will change its plane and it becomes non-planar.And non-planar compound is what?Can be non-planar.This is,this is,that's what I said.This is experimental.No,I told you this thing that basic thing is what?Huckelstrom conjugation and all.But there are many compounds in which different,different cases we have.That's why we are doing all these examples.So you have to keep this in mind.When the molecule has,right on this one,the last one,right on.When the molecule has 7 or more atom present,cyclic molecule.7 or more atom present.When the molecule has 7 or more atom present.It will never be anti-aromatic.Because it is highly unstable.Gamma,the molecule changes its plane and becomes non-aromatic.Changes its plane and becomes non-aromatic.We can do it.Sir,but changes its plane give me that like 4.It's like this part is in other plane and this part is in other plane.So overall the molecule becomes non-planar.7 atoms in the main chain.7 atoms in the main chain.Cyclic only we are considering.Not total.Side chain we won't consider.So overall what we can say,7 atom is present and aromatic possible.Anti-aromatic is not possible.So only two answers possible in this case.Aromatic or non-aromatic.If it has 4n plus 2 pi electron,aromatic,otherwise it will be non-aromatic.Anti-aromatic won't be possible here.One more thing you see here.This pyridine has this lone pair available.And pyro,this lone pair is in conjugation with this pi bond.It means in other word what we can say.This lone pair is available on this nitrogen atom.But this lone pair is involved in resonance.It is delocalized.This lone pair is delocalized and this lone pair is localized.Localized means present on the atom.That term we use for this.This lone pair is localized.This is delocalized.So if you have to compare the basicity of these two molecules.Pyridine and pyrrole.Pyridine the lone pair is available.So it can donate lone pair.That's what the basic nature.So basicity of pyridine is more than to that of pyrrole.Because this lone pair is delocalized.So it is not available.It cannot donate.So basicity decreases.Right?Right on the basicity of pyridine is more than to that of pyrrole.More than to that of pyrrole.Since the lone pair.Since the lone pair on nitrogen atom.Lone pair on nitrogen atom.In case of pyridine.Since the lone pair on nitrogen atom.In case of pyridine.Is available.What about this one?So is it not available?It's not available.8. xenonite.設計用 7. protests. ports.or battles.Sellenonite.send odor.这一个是 non-automatic因为7 颜色都在24685根据那样,应该是 anti-automatic因为我们有7个颜色所以我们将这些颜色混合不是 anti-automatic这是什么还是 non-automatic这是 also non-automatic这是 sp3 hybrid IC根据那样,不是我们将这些颜色混合但是这是什么sp3 hybrid IC这些颜色是为什么是 sp3我们会有 hydrodynamic我们会有 hydrodynamic好的4 颜色不可能有 any sp3sp3根据这些颜色你看,我们有根据到这里这部分是 non-automatic这部分是 non-automatic为什么是 anti-automatic因为1 颜色是 sp3 hybrid IC整个颜色是 non-automaticsp3 如果是 non-automatic这些颜色是因为我们有根据到这里但是这部分是 non-automatic这部分是 non-automaticautomaticautomaticity in case ofautomaticity in case ofmulticyclic compoundmore than one cyclic structureI will write down some structure heremore than one cyclic structureI will draw some structure heremulticyclic compoundin this case we only countthe peripheral pi bondor pi electronsin this case we only countthe peripheral pi electronsfor example you see this oneyou said we only considerthe border electronwhat if something in the middleis somehow sp3 hybrid ICsp3 is not possiblemiddle in sp3 is not possiblein this case we will countthe peripheral pi electronsso 1 2 3 4 55 pi electrons is10 pi electrons10 electrons is what4n plus 2 is aromaticok1 2 3 4 5 612 pi electronsthis is whatanti aromaticanti aromaticokthis one you seewe only countperipheral pi electronsthis one isnon-peripheral pi bondand hence we won't count thisokso we have only1 2 3 4 5 6 714 pi electronsand it is aromaticnon-peripheral meansthis isnon-peripheral pi electronsacross this boundaryokthe common bondbetween therangeok this including this two ringsor this bond which we havemeans only what you have to doyou have to follow thisonly this bondthis bond we won't considernon-peripheral pi bondwe won't count itone more thing you seeif you have a molecule like thisokwrite down in this oneload firstwe will see thecopy down this oneso it's not for theit's not for theit's not for thewrite downmulticyclic compoundsmulticyclic compoundswill beeither aromaticor anti-aromaticeither aromaticor anti-aromaticnon-aromatic isnot possible hereokso when you look at thisstructure rightthis structurethis carbon atom is whatit's SP3that's why this becomes whatnon-aromaticbut like I saidit cannot benon-aromatic hererightthen what we dothe larger ring is thiscorrectthen we check the nextsmaller ring into thiswhich is nothing but this onetwo rings we have hereone is thisanother one is thisthis is moleculeokso the larger ringwe'll see firstif it is non-aromaticwe'll gowe'll check the nextsmaller ringif again you'll getnon-aromaticwe'll check anotheraromaticor anti-aromaticin this resonationis not possible rightlikesorryresonancelike in thein the rectanglein this oneit's not possiblebut hereit's possibleso becauseof this onlythe molecule ishighly stable hereso do you seeyou seesee seein aromaticitystill the researchis going onwe areonly thehuckles rule isnot thecorrect thingbecause I havegiven you many exampleswherehuckles rule isnot possibleand it isaromaticor anti-aromaticcompoundsso in thissectionyou have tokeep theseexamples in mindthis compoundis highlystable compoundokand that's whyI'm givingitcan not benon-aromatichow do you knowthat moleculeis aromaticor anti-aromaticso first we'llcheck the larger ringright it isnon-aromaticnot possiblethen we'llcheck the nextsmaller ringif it isnon-aromaticagain we'llcheck the nextsmaller ringtill we getaromaticor anti-aromaticlike for thisone you seethis compoundis SP3non-aromaticthe nextmolarthis oneokaythis onethis onerightthe first ringyesif that isnon-aromaticwe'llcheck the nextsmaller ringthen againnextsmaller ringlike for examplethis oneyou seenotseparatedcheckwhen wecheck therectangular第一个叫做 non-aromatic, 这个叫做 anti-aromatic这个叫做 non-aromatic, 这个叫做 anti-aromatic这个叫做 anti-aromatic这个叫做 non-aromatic这个叫做 non-aromaticOK, one comparison will do the last examplebond is alpha, this bond is thetayou have to compare the bond order of alpha and bond order of thetaand then bond is alpha第二个叫做 non-aromatic我们可以改变这个 π-electron, 无论是这个银子, 还是这个银子因为两个都是同样的, π是 σπ, π是 σπ所以我们可以改变这两个如果我们改变这个 π-electron, 或这个银子, 那就好了我们只要改变这个银子, 这个变成 negative, 这个变成 positive我们不要放弃, 这个变成 π-electronOK, and here, if you shift this here这个变成 positive, and this is negative现在因为这个银子, 这个银子是什么?aromatic, π- σ, 246, aromaticand this is what?also aromaticboth ring are aromatic herethis ring is what?and this ring is what?aromaticso if you compare this two, this compound is more stiffit means this shifting is what?easy other than this shiftingit means this bond order here is close to oneand here it is close to twoso bond order of alpha is less than the bond orderso in that part, the peak of orderwe have to determine if it was anti-aromatic or aromaticwhich one?because you said we should pick an orderawesome, if you shift here also you get the same numberthat won't changeif you shift this herethis ring becomes anti-aromaticthis ring becomes aromaticwhy this shifting is there?because according to this, it is getting aromaticity, stabilitythat's why this shifting will be positivegreater what?stability greater the bond orderno, bond ordering is not for moleculeit's for the bond between the two atom in a moleculeno, no, nosee, this bond order is two herewhat is the bond order here?one, if this is more stableit means this molecule wants to be in this formit means bond order is closer to one hereright, here bond order is twobond order is one but this one is less stable than thisthat's why this molecule wants to be in this formright, the bond order is closer to onethat's why we do the comparison nowin that second stageone of them is anti-aromaticand one is aromaticso it's the whole molecule anti-aromaticno, we cannot talk about the whole molecule hereit says this part is aromaticanti-aromatic, this part is aromaticso the whole molecule won't have the stabilityas aromatic compound for anti-aromaticso it is somewhere in this viewyou are not seeing meno it's notsee that'sthis oneso this oneit's notit's notpossibly you can draw thisbut this is stated as aromaticnobut I can read the pointno it's notsee that'sso how to use thatthat is more stable than this onethat is more stablethis onethat's more stable than thatno this is actuallythe half part is aromaticanti-aromaticwe are seeingwe are not comparing the stability of this twowe are comparing the stability of this tworightthis one in the both part is aromaticit means this has more tendency to convert it to this formbecause you are getting stability here aromaticto convert it to thisbut this has less tendency to convert it to thisbecause this is anti-aromaticthat's why the bond order here is close to twoand here it is close to onewe canunderstoodthis oneboth becomes anti-aromatic nowthat's why this conversion is not possibleif you have this optionthen this will go towards stabilitynowhy this will form anti-aromaticthis onerightin general it doesn't say thatif something has a bond orderthat's highbond order is highstability will be moreof that bondso you are always saying stabilityno noagain you are thinking me wrongI am not talking about the stability of this bondI am talking about the stability of that moleculethis is more stable than thisthen this rightthis molecule has tendency to exist in this formrightthis molecule has lesser tendency to exist in this formin comparison to thisso when this molecule exists in this formhere the bond order is whatoneso we can saysince this is more stable than thishere the bond order is closer to oneand this will only be more stable than thisso bond order is closer to twothat's why bond order of beta is more than that of alphabond length will be whatreverse is not possiblethat's why from thisthis is not possiblebecause the idea is say helloboth becomes anti-aromaticthe stability will be whateverthat's why this will formok