 Hi and welcome to the session. Let us discuss the following question. The question says evaluate the following term and the next class is 1 to 22. Limit of sine a x by dx as x tends to 0. Before solving this question, we should know that limit of sine x by x as x tends to 0 is 1. The knowledge of this result is the key idea in this question. Now we can get the solution. In this question we have to evaluate limit of sine a x by dx as x tends to 0. We will make use of this result to solve this question. Now in order to make use of this result, we have to make angle of sine and denominator to be same. So we will now multiply and divide this expression by a. So now this is equal to limit a x tends to 0 because x tends to 0 implies a x also tends to 0. Sine a x by a x into a by b. You should also know that limit x tends to a c into fx where c is a constant is equal to c into limit x tends to a fx. Now here a by b is a constant. So limit of this expression is equal to a by b into limit a x tends to 0 sine a x by a x. Now this is equal to a by b into limit y tends to 0 sine y by y where y is equal to a x. In the key idea we have learnt that limit of sine x by x as x tends to 0 is 1. So this means limit of sine y by y as y tends to 0 is also 1. So this is equal to a by b into 1. This is equal to a by b. Hence our required limit is a by b. So this completes the session. I am taking care.