 Hi and welcome to the session. Let us discuss the following question. Question says, find the general solution of the differential equation dy upon dx plus square root of 1 minus y square upon 1 minus x square is equal to 0. Let us now start with the solution. Given differential equation is dy upon dx plus square root of 1 minus y square upon 1 minus x square is equal to 0. Now subtracting this term from both the sides of this equation, we get dy upon dx is equal to minus square root of 1 minus y square upon 1 minus x square. Now let us name this equation as equation 1. Now separating the variables in equation 1, we get dy upon square root of 1 minus y square is equal to minus dx upon square root of 1 minus x square. Now integrating both the sides of this equation, we get integral dy upon square root of 1 minus y square is equal to minus integral dx upon square root of 1 minus x square. Now using this formula of integration, we can find this integral as well as this integral. Now integral of dy upon square root of 1 minus y square is equal to sin inverse y and this integral is equal to sin inverse x. We will write this minus sign as it is and here we will write sin inverse x plus c, where c is the constant of integration. Now adding sin inverse x on both the sides, we get sin inverse y plus sin inverse x is equal to c. So the required general solution of the given differential equation is sin inverse y plus sin inverse x is equal to c. This completes the session. Hope you understood the solution. Take care and have a nice day.