 Hi and welcome to the session. I am Asha and I am going to help you with the following question which says let A be a set of elements having X, Y and Z and B be a set of elements having 1 and 2. Find the number of relations from A to B. Now as we move the relation from A to B is a subset of the Cartesian product of A and B. Therefore the number of relation from A to B is equal to the number of subsets of the Cartesian product of A and B. So this is the key idea we are going to use in this problem to find its solution. Let us now start with the solution. And here we are given a set A having elements X, Y and Z with a set B having elements 1 and 2. Now we are required to find the number of relations from A to B and we know that the relation from A to B is a subset of A cross B and A cross B is equal to the ordered pairs X1, X2, Y1, Y2, Z1 and Z2. We have 6 members in the Cartesian product. Therefore number of subsets of A cross B will be 2 raised to the power 6 which is equal to 64. And by a key idea we know that number of subsets of A cross B is equal to the number of relations from A to B. Therefore number of relations from A to B is equal to 64. So our answer is 64. So this completes the solution. Hope you enjoyed it. Take care and have a good day.