 Hello and welcome to the session. In this session we discuss the following question which says if A, B, A, C, A, D and A, E are parallel to a line L, then prove that A, B, C, D and E are collinear. Before proceeding with the solution, let's recall Euclid's fifth postulate. According to this we have that for every line L and for every point P not lying on L, there exists a unique line passing through P and parallel to L. This is the key idea to be used for this question. Now we move on to the solution. We are given net lines A, B, A, C, A, D and A, E are all parallel to the line L. So this means that A is a point outside the line L through which A, B, A, C, A, D are drawn parallel to the line L. That is we have drawn four lines from the point A which are parallel to the line L. But from Euclid's fifth postulate we have that for every line L and for every point P which is not lying on L, there exists a unique line M passing through P and parallel to line L. That is by Euclid's fifth postulate one and only one line can be drawn through A and parallel to L and this is possible only when the points A, B, C, D and E all lie on the same line. So when the points A, B, C, D and E will lie on the same line then only one line can be drawn from the point A which is parallel to the line L. Hence this means that the points A, B, C, D and E are collinear. So just complete this session. Hope you have understood the solution for this question.