 Hello and welcome to the session. In this session we discussed the following question which says two triangles A, B, C and D, B, C are on the same base B, C are on the same side of D, C in which angle A equal to angle D equal to 90 degrees. If C, A and B, D meet each other at E, show that A, E into E, C is equal to B, E into E, D. Let's move on to the solution. This is the figure where we have triangle A, B, C and triangle D, B, C on the same base B, C and on the same side of B, C and we have angle A and angle D as 90 degrees and C, A and B, D meet at the point E. So first let's write down what all is true to us. We have that angle A is equal to angle D equal to 90 degrees and we have to show that A, E into E, C is equal to B, E into E, D. First we have that in triangle A, B and triangle D, E, C, angle A is equal to, angle D is equal to 90 degrees which is already given to us. Then we have angle A, E, B is equal to angle D, E, C since they are vertically opposite angles. Thus we say triangle A, E, B is similar to triangle D, E, C by A, A similarity criterion and thus the corresponding sides would be in the same ratio. Therefore we have A, E upon D, E is equal to B, E upon C, E equal to A, B upon D, C. Let's consider this. So from here we get A, E into C, E is equal to B, E into D, E or we can also say A, E into E, C is equal to B, E into E, D. So hence proved. So this completes the session. Hope you have understood the solution of this question.