 Hi and welcome to the session. Today we will discuss the following question. It says, a die is thrown once, find the probability of getting first a prime number, second a number divisible by 2. Before moving on to the solution, let's see how to find out the probability of an event. Probability of an event E is given by number of outcomes favorable to the event E upon number of all possible outcomes of the experiment. This is the key idea we will be using for this question. Now let's move on to its solution. First of all, we are given that a die is thrown once and we know that a die has six faces numbered as one, two, three, four, five and six. So that means these all will be the possible outcomes. Thus number of all possible outcomes will be equal to six. Now let's see the first part. In this we need to find out the probability of getting a prime number So let us assume E to be the event of getting prime number. Now from the numbers one, two, three, four, five and six, prime numbers are two, three and so that means outcomes favorable to the event E are two, three and five. So from this we have number of outcomes favorable is three because there are three outcomes which are favorable to E. Now from the key idea we know that the probability of an event is given by number of outcomes favorable to the event E upon number of all possible outcomes. So here the probability of the event E that is the probability of getting a prime number will be equal to number of outcomes favorable to E that is three upon number of all possible outcomes that is six. So this will be equal to one upon two. Thus one upon two is the required probability for the first part. Now let's see the second part. Here we need to find out the probability of getting a number divisible by two. So for this also number of all possible outcomes will be six and the numbers which are divisible by two will be two, four and six. So here first of all let us assume that F with the event of getting a number divisible by two. So here the outcomes favorable to the event F will be two, four and six. Thus the number of outcomes favorable to the event F will be three. Now the probability of the event F that is the probability of getting a number divisible by two will be equal to number of outcomes favorable to F that is three upon number of total possible outcomes that is six. So this will be equal to three upon six that is one upon two. Thus for the second part also the required probability is one upon two. So with this we finish this session. Hope you must have understood the question. Goodbye take care and keep smiling.