 Hi, and welcome to the session. Today we will learn the construction of a triangle when the lengths of its three sides are known that is SSS criterion. Let us construct a triangle PQR in which PQ is equal to 5.3 centimeters, PR is equal to 4.6 centimeters and QR is equal to 3.8 centimeters. First of all let us draw a rough sketch of triangle PQR and write all the measurements on that figure. So here is the rough sketch of triangle PQR. We are given PQ is equal to 5.3 centimeters, PR is equal to 4.6 centimeters and QR is equal to 3.8 centimeters. So now let us understand the construction of triangle PQR. First of all let us draw an aligned segment PQ of length 5.3 centimeters. So here we have aligned segment PQ of length 5.3 centimeters. So our first step of construction is draw a line segment PQ of length 5.3 centimeters. Now PR is equal to 4.6 centimeters. So with P as center and radius 4.6 centimeters draw an R like this. Now point R will lie somewhere on this R. So our second step of construction is with P as center and radius 4.6 centimeters draw an R. Next we have QR is equal to 3.8 centimeters. So now with Q as center and radius 3.8 centimeters we will draw an R to cut this R at point R. So this is the point R. Our third step of construction is with Q as center and radius 3.8 centimeters draw an R to cut the previous R at point R. Now join PR and QR to get the triangle PQR like this. So triangle PQR is the required triangle and here PR is equal to 4.6 centimeters and QR is equal to 3.8 centimeters. Thus our last step of construction is join PR and QR and so triangle PQR is the required triangle. With this we finished this construction. Hope you must have understood it. Goodbye, take care and have a nice day.