 Hello all and welcome to the session. Today the question is construct a triangle ABC in which BC is equal to 5.4 centimeters and the B is equal to 60 degrees and AB is equal to 4.5 centimeters. Draw the in circle of triangle ABC. Now, let me start with the solution. First of all, we will make a rough diagram of triangle ABC in which BC is equal to 5.4 centimeters, AB is equal to 4.5 centimeters and angle B is equal to 60 degrees. Now, we will start with the steps of construction. In the first step, we will draw line segment BC is equal to 5.4 centimeters. As you can see here, we have drawn a line segment BC is equal to 5.4 centimeters. Now, in the second step, construct a angle CBX is equal to 60 degrees. Here, we have constructed an angle CBX, which is equal to 60 degrees. Now, in the third step, with B as center and radius 4.5 centimeters, draw an arc cutting the rail BX at the point A. Now, you can see here, we have drawn the B as center and arc of 4.5 centimeters, which is cutting the rail BX at the point A. Now, in the fourth step, drawing AC and by drawing AC, we can see here, we are cutting the triangle ABC, which is the required triangle. So, therefore, triangle ABC is the required triangle. Now, in the next step, draw BE and CA by sectors of angle B and angle C respectively, meeting each other at O. Now, you can see here, we have drawn the bisector of angle B as BE and bisector of angle C as CF and these two are meeting at point O. And now, draw OL perpendicular to BC. You can see here, we have drawn OL perpendicular to BC. Now, in the next step, with O as center and OL as radius, draw a circle Now, you can see here, with O as center and radius S OL, we have drawn a circle, which is touching all three sides of the triangle and this circle is called the in-circle of the triangle ABC. Therefore, this is the in-circle of the triangle ABC. So, this is the required construction and that's all for this session. Hope you all have enjoyed this session.