 Hi and welcome to the session. Let us discuss the following question. It says, what are the points on yx's whose distance from the line x upon 3 plus y upon 4 is equal to 1 is 4 units. To solve this question we need to know the distance of a point say x1 y1 to the line say ax plus vy plus c is equal to 0 which is given by mod of ax1 plus vy1 plus c upon under root of a square plus b square. So this knowledge will work as key idea. Let us now proceed on with the solution. We have to find the points on yx's. So if we have any point on yx's x coordinate must be 0 because yx's is the line x is equal to 0. So let 0 a be any point on yx's. Now the distance of the point 0 a to the line x upon 3 plus y upon 4 is equal to 1 is given by mod of 0 upon 3 plus a upon 4 minus 1 upon under root of upon 3 square plus 1 upon 4 square. This is by using the formula for distance of a point to the line and here a is 1 upon 3 and b is 1 upon 4 and c is minus 1. Again this is equal to mod of a upon 4 minus 1 upon under root of 1 upon 9 plus 1 upon 16 and this is again equal to mod of a upon 4 minus 1 upon under root of 16 plus 9 upon 144 taking the LCM. Again this is equal to mod of a upon 4 minus 1 upon under root of 25 upon 144 which is again equal to mod of a upon 4 minus 1 upon 5 upon 12 and this is again equal to 12 upon 5 into mod of a upon 4 minus 1 and we are given that this distance is 4 units so the distance is 4 units so this implies 12 upon 5 into mod of a upon 4 minus 1 is equal to 4. And this implies mod of a minus 4 upon 4 is equal to 4 into 5 upon 12 and this implies mod of a minus 4 is equal to 4 into 4 into 5 upon 12 now 4 into 3 is 12 so this is equal to mod of a minus 4 is equal to 20 upon 3 and this implies a minus 4 is equal to 20 upon 3 or a minus 4 is equal to minus 20 upon 3 this implies a is equal to 20 upon 3 plus 4 or a is equal to minus 20 upon 3 plus 4 this again implies a is equal to 32 upon 3 or a is equal to minus 8 upon 3 hence the points on y axis are 0 minus 8 upon 3 and 0 32 upon 3. So this completes the question hope you enjoy this session goodbye and take care.