 follow and welcome to the session. My name is Mansi and I am going to help you with the following question. The question says, find the equation of the circle with center minus a minus b and radius under the root a square minus b square. So let us start with the solution to this question. Now it is given to us that center of the circle that is the point hk is equal to minus a minus b and radius that is r is equal to under the root a square minus b square. Now we also know that equation for the circle is given by x minus h the whole square plus y minus k the whole square equal to r square where hk the point hk is the center for the circle and r is the radius. So now what we do is we simply put in the values of hk and r from this we get x minus of minus a is x plus a the whole square plus y minus of minus b is y plus b the whole square equals to under the root a square minus b square the whole square. Now this implies x square plus a square plus 2 ax plus y square plus b square plus 2 by is equal to square of under the root a square minus b square is a square minus b square this implies x square plus y square plus 2 ax plus 2 by is equal to a square minus b square minus a square minus b square. Now plus a square gets cancelled with minus a square and we have x square plus y square plus 2 ax plus 2 by now minus b square minus b square becomes minus 2 b square and when we bring it to the left hand side it becomes plus 2 b square equal to 0. So we say that our answer to this question is that equation of the circle with center minus a minus b and radius under the root a square minus b square is given by x square plus y square plus 2 ax plus 2 by plus 2 b square is equal to 0. So this is our answer to the question. I hope that you understood the question and enjoyed the session. Have a good day.