 Hello and welcome to the session. Let's work out the following problem. It says prove that cos a upon 1 minus 10 a minus Sine square a upon cos a minus sine a is equal to sine a plus cos a so let's now proceed on with the solution and Let's start The solution and we'll be first dealing with LHS LHS is cos a upon 1 minus Than a minus Sine square a upon cos a minus sine a Now again cos a upon 1 minus then a can be written as Cos a upon Then a sine upon cos a minus Sine square a upon cos a minus sine a right Now again cos a upon now taking LCM So we'll have cos a into 1 minus sine a Upon cos a because LCM here would be cos a minus sine square a upon cos a minus sine a now again this can be written as cos a upon 1 into cos a upon cos a into 1 is cos a minus sine a minus sine square a upon cos a minus Sine a a cos a into cos a is cos Square a upon cos a minus sine a into 1 is Cos a minus sine a minus Sine square a upon cos a minus Sine a now taking LCM LCM would be cos a minus sine a and in the numerator we have cos square a minus sine square a now cos square a minus sine square a can be written as cos a minus sine a into cos a plus sine a upon cos a minus Sine a here we have used the formula of a square minus b square which is equal to a minus b into a plus b Here a is cos a and b is sine a now cancelling cos a minus sine a from the denominator and the numerator we have cos a plus Sine a which is same as sine a Plus cos a and this is the RHS hence LHS is equal to RHS So this completes the question right for now take care. Have a good day