 Hello and welcome to the session. In this session we will discuss about large numbers in details. Now length is measured in millimetres, centimetres, litres and kilometres. Here 10 millimetres is equal to 1 centimetre, 1 metre is equal to 100 centimetres which is equal to 1000 millimetres. Also 1 kilometre is equal to 1000 metres. Now weight is measured in grams and kilograms. Here 1 kilogram is equal to 1000 grams. Also the capacity is measured in litres and millilitres. Now 1 metre is equal to 1000 millilitres. Now let us see one example. Weight of 1 box is given as 4 kilograms 500 grams. Which is equal to now to change kilograms into grams we multiply it with 1000. So it will be 4000 grams plus 500 grams which is equal to 500 grams. Now it is given that van can carry which can be changed into grams by multiplying this with 1000. So it will be 8 lakh grams sum of liberation. Now we have to find the number of boxes a van can carry. The number of boxes total weight which a van can carry and this is the weight of 1 box. So putting these values here this will be equal to 8 lakh which on solving is equal to 177.77. Now we cannot put 177.77 boxes in a van at the 10th place weight to the digit at the 10th place. That digit is the digit at the 1th place which is 6 less than the digit at 10th place the digit at 1st place. But in the second case is greater than 5 used by 1 so it will become 5 plus 1 is equal to 6. And the digit at 1's place that is to consider the digit on the right to the digit at the 10th place which is the digit at the 1's place. And that is 3 but 3 is less than 5 which is 3 will be changed to 0. 63 estimating to the nearest 100's we have to round off this number to the nearest 100's this digit is at the 100's place. This at the 10th place and this at the 1's place. Now here we will consider the digit on the right to the digit at the 100's place. And the state is so the digit at the 10th place this 3 is less than 5 at the 100's place which is 8 will remain as it is. The digit at the 10th place which is 3 will be changed to 0 and the digit at the 1's place will be also changed to the rounding of 836 to the nearest 100's to 800's. Now let us nearest 1000's by rounding off 924. Now here we have to round off this number to the nearest 1000's and here this number is at 10,000's place. This number is at 1000's place this at 100's place this at the 10's place and this at the 1's place. Now for rounding off this number to the nearest 1000's we will consider the digit which is on the right to the digit at the 1000's place. And that is the digit 9 which is at the 100's place. 9 is greater than 5 at the 1000's place used by 1 so it will be is equal to 6. The digit at the 100's place which is 9 will be changed to 0. The digit at the 10's place which is 2 will be also changed to 0. The digit at the 1's place which is 4 will be also changed to 0. Therefore on rounding off 924 let us learn how to estimate. Let us take the first example in this digit sum of 2654 to 293. We will round off these numbers on rounding off 654 to 3000. Now let us see one more example. Now for this we will round off these numbers to the nearest 100's. And here on rounding off 5673 to its nearest 100's estimated difference. So by taking the 300's and which is the product. Now let us see an example. We have to find the estimated product of 578th estimated product. We will round off, we will multiply the greatest place which is the 100's place. So rounding off 578 to the nearest 100's the greatest place is the 10's place. The estimated product is 2 numbers. The numbers it will give 36000 is the estimated product. We have learnt about large number in details and estimation. So this completes our session. Hope you all have enjoyed the session.