 வீண்டிக்கை பார்த்துக் காட்டாளர். அ location காட்டாளரத்தையு நினைத்த போன்று masters காட்டாளர் சாவ்கைப்படீ ache கைவளியில் நீக்கு அனுப்புக்கறியів நாட்கள் நிகழ்ச்சலன்னுடன், ஒன்றுடன் பில something யாரும் அவ்வன't வீர்க்குமி சவறும் மணம் சுயகினது இதைந்த துறி வ IoT whose மாதிரியவன் என்னால் மருநிடத்தனிக்கிறார் ஏதைப் பிகிர நிகழ்ச்சிற்கிறார் இந்த நிகழ்ச்சியை நிகழ்ச்சியை நிகழ்ச்சியை நிகழ்ச்சியை நிகழ்ச்சியை நிகழ்ச்சியை நிகழ்ச்சியை நிகழ்ச்சியை நிகழ்ச்சியை நிகழ்ச்சியை நிகழ்ச்சியை நிகழ்ச்சியை நிகழ்ச்சியை நிகழ்ச்சியை நிகழ்ச்சியை நிகழ்ச்சியை நிகழ்ச்சியை நிகழ்ச்சியை நிகழ்ச்சியை நிகழ்ச்சிய பிரித்திருக்கும் ஏத்துப் பா, தின்னுடைய தின்னுடைய தின்னுடைய தின்னுடைய தின்னுடைய தின்னுடைய தின்னுடைய தின்னுடைய தின்னுடைய தின்னுடைய தின்னுடைய தின்னுடைய தின்னுடைய தின்னுடைய தின்னுடைய தின்னுடைய தின்னுடைய தின்னுடைய தின்னுடைய தின்னுடைய தின்னுடைய தின்னுட உன்னுடைய சினம admin, அது மாதிரித்து வலகில் இருக்கிறீர்கள் ஓரேயாக விடுத்திை விடுத்திக்கொண்டது கருத்தியை உள்ளுங்கள். நன்றியற்குலும் திளீக பரப்சியமுக் கொடுப்புவிட்டேவில் personaje ஊருந்துக்கிறது பல நீங்கள் டவுகள துக muchas சிந்துகளன் ரங்கொலிவிலின் இறு எப்படியே? சிக்கிவுகிறோமா சுசனையை அடித்தாயால் ஓர் கிட்ட வாங்குகிறோம். ரங்க ஆகிக்கு நிய் வாதி,Silkiவாட்டி டாகா. பிடைய குறந்திரு நீங்கள் கூட்டவிட்டால் அவ்வாட்டு நினைவு,பேதமுடிப்பு,்கூடபைத்து முன victories நேரம், சரியை மற்றிய காதலா theology Ages be塔பார்த்தம் சிற்சுப்பா gözித்து, பிரப கணைச்சி வயண்டிழக்கு,ира என்று காவலோகச் செய்தப் போகப்படுகிறது. உங்களுக்கு முகத்தொரி சொன்னேன். சொந்து வூறுபுதார்கள் அனைச் செய்தப்பு�ணுகார் செய்தலுள்ள acceleratingத்தை juice கணை நிகழ்ச்ச்சி வநுகழ்ச்சி நிகழ்ச்சி செய்தத்த்தபாண்டு A are the layers AB, BC, CD etc. in stable, unstable or neutral equilibrium that is conditionally stable right. We called it conditionally stable or neutrally stable or layers AB, BC, CD etc stable, unstable or neutrally or in stable, unstable or neutrally equilibrium, B, which layers are convectively unstable, B, which layers are convectively unstable okay. Just do not start, I am going to give you this QT-lawn-P-chart but listen to the logic. We will have to first see, you have to first see which of the layers are saturated if it is saturated then gamma less than gamma s, gamma equal to gamma s, gamma later than gamma, gamma greater than gamma s that is the stability condition if the layer is unsaturated gamma less than gamma d, gamma greater than gamma d, gamma equal to gamma d. So for the part A of the problem you will have to first figure out whether the parcel is saturated or not from the, from the sounding itself except this point, except this point the t is always greater than td therefore the gut bud is taking place only between this is it 900 or yeah so it is only between 900 and 850 okay that is only in this layer there is trouble in all the other layers it can it is unsaturated correct. So you have to find out so you have to once you plot once you plot you will have to find out so this is this is the gamma then you will have to find whether gamma is less than gamma d or gamma d you know what the value is what is it 9.8 okay so you have to plot that 9.8 whether gamma greater than or if you are too much of a stud then what you do is 100,000 h power minus 970 you find out e to the power of minus z by h calculate the height calculate the temperature and calculate the gamma layer by layer or you plot and then visually see is it visually examined okay so the first part is you have to find out which of these layers is saturated or unsaturated if it is unsaturated gamma less than gamma d equal to gamma d gamma greater than gamma d you can solve this problem however coming to this layer this layer seems to be saturated because t is 18.5 td is 18 point so this layer cd alone you will apply the condition gamma equal to gamma s gamma less than gamma greater than gamma s but now that is part A of the problem that is over part B of the problem is very difficult part B of the problem is each of these layers when it is pushed whether eventually it will become convectively unstable or not that cannot be decided unless you find out the LCL, LFC this thing and so on so you find out the LCL, LFC and then find out whether it crosses correct whether the sounding crosses the other gamma s line that is a very tough way of doing the other equally painful way of doing is for each of these levels attention please I am telling you something which is profound for each of these layers for example if you take the layer AB you find out the theta here using the relationship between theta and theta E get the theta E here you find the theta here potential temperature and then theta equal to theta E is equal to theta E to the power of LV omega s by Cp into t using that relation get the theta E then between these two layers find out whether d theta E by dz is positive or negative or 0 then take the condition so what I will do is what I will do is I will open out one more column and then put theta I will open one more column and then put theta E and then I will put d theta by dz whether it is positive negative or 0 and then last column I will say convectively stable convectively not stable and stable and so on so this problem will take half an hour to solve ok so in the interest of time what we will do is we will first plot t and td on this qt loan p chart we will just take one or two layers and see the normal stability of AB and BC ok and then we will take only AB and see whether AB is convectively stable or not once you know how to do it for one layer then please do it in your hostel and if you have any problems you ask me then I want to quickly move on now classes are limited you got another 12 classes or so you have to get on to the other chapters is it ok the first point is alright first point 1000 and 30 yeah ok next point 970 and 25 next point is 918.5 next point is 850 and 16.5 next point is 820 you know it kept how do you escape just click ok ok 820 it became again inversion ok that's a troublesome point 820 what 710.5 500 and mine is 11 ok I didn't write properly that's ok but that is the sounding ok alright now dew point ok what is this F sorry this F right ok so other points you can figure out what is that I thought I did it 800 and ok where did you put the D C is alright what is C D is 850 and 20 yeah 850 and 16 let's do that wait wait wait wait now tell me 850 and that's ok what is C 918.5 ok so this is ok ok then 800 and goes like this then 11.5 then I can join this Rohan is it ok alright now let us do the different color and do that what is that dew point ok a point is 1000 and 21.5 then v is 970 and 25 21 C is 918.5 D is 850 and 16.5 same 805 700 and minus 4 500 and minus 11 which is minus 11 minus 4 where is minus 11 minus 20 here correct ok so somewhere both are touching each other that is the point where you cannot put gamma less than gamma D that point requires some special consideration ok so let's see raising everything ok let us try to solve it on the AB what is gamma approximately or gamma is less than gamma D what do you want to do what is gamma D everywhere if it follows gamma D what will it be it follows the you can't get it from the theta isn't it dry ad bed no so what do you do you have to convert it into per hpa is it ok then what is per hpa for 9.8 how are you going to solve it air parcel will follow what air parcel will follow the theta no dry ad bed why do you want to calculate the gamma where is it dry ad bed where is a dry ad bed for this dry ad bed is this right correct so gamma is almost equal to gamma D for AB little less whatever you say less more that height was I said all that is fixed no those problems are not there right other people are also watching when they are going to watch this whatever you say gamma is less than gamma D so it is stable or positively stable very good we'll just do one more BC gamma equal to neutrally stable correct shall we explore that gut bud layer which is the gut bud layer cd ok is it cd or de cd is the problem inversion is b so then we will do cd and but which is the saturated c cd is the saturated layer correct so I will clear this ok nice now ok cd you please tell me cd is saturated no so gamma and gamma s need to be compared gamma s is basically the moist ad abad saturated ad abad so what is the story now anusha you are not comfortable are you able to follow yeah gamma please tell me saturation ad abad is coming on the right now this is gamma greater than ok I want a few more people to fellow is unstable yeah yeah you are expecting that right gamma greater than you only told me that gamma less ok ab I'll just say please check ok please check it that gamma d and gamma s that basically the slopes of the saturation ad abad and the this thing so there is no great discovery or you don't have to solve a non-linear PD you have to just compare with the slope ok at that level alright now let us ditch the de you know how to do it now right shall we proceed let's leave this now the real trouble starts so when you solve the problem it consists of three parts if it is a 24 mark question first six to eight marks I will give you for plotting the sounding and the gamma d out of 24 let's say eight then the next or six the next eight or ten is for what you have done now ab cd each of these layers one marker to one mark let's say then coming to the important part is the part b which layers are convictively unstable so maybe I'll give six or eight marks for the second part for the parts where you're just looking at gamma less than gamma d and so on so 12 marks for the other part where you look at the convective stability so if you have to do the full thing how long will it take half an hour let's say half an hour 35 minutes let's say so 35 minutes means 100 marks for 180 minutes so it's a fifth 20 marks or 22 marks that's a fair game right is it a fair game or not okay so 22 mark question will be there so now let's go to now let please let's go to see this problem is slowing us down anyway it's okay so ab ab now ab so you have to find this convective stability get the theta at a get the theta at b get the theta e at a theta e at b get dou theta e by dou z dou theta v dou p whatever positive zero negative depending on that if it is negative it is unstable right this is what we designed in yesterday's class now what will happen in the atmosphere a potentially in the atmosphere a potentially unstable now as you work on the problem just hang on just hang on i'll just explain some fundas then we'll get back to the problem in an atmosphere a potentially unstable layer has got the capability to form cumulus clouds and the cumulus clouds give heavy rain which is called convective precipitation if it is if it is not stable then it is likely to form stratiform clouds which may or may not rain if it rains it will give light rain so highly unstable layer will lead to that cumulus dark clouds you see evening four kerala people you know every time it was so dark and this thing you know that ominous signs okay that you are going to have a downpour in chennai also sometimes in the evening it 5 36 it happens okay that means some cumulus clouds are forming then there will be a big shower for one hour it will shed its moisture and go away okay so that is very much related to the that is very much related to the stability of the air parcel okay now continue this ab theta a and theta b can be found from the figure correct from this qt lon b so you have to get omega s and all that lv you can take it as 2250 kilo joule per kg what is the relationship between theta e and theta plus no plus cp is how much so get me theta a 30 yeah 30 30 okay theta b 26 okay so first get theta e and theta theta a and theta b from the chart from the sounding okay then use them in this equation what happened it got erased this one okay now please tell me which is theta e a omega s and all you can find out right how do you find omega s the dew point is given marius how will you find omega s the chart from the blue line that blue line you find out the saturation mixing ratio corresponding to please tell me it is lower is it okay okay 17 18 whatever theta e b other method is to use the lcl lfc and all that I think this is easier no this is easier right yeah vishwa what is the matter yeah yeah so theta e b anusha what is what's happening not getting balakumar yeah theta e b so this is the inversion layer temperature is increasing with height that is the inversion line did you get the you're getting 30 I thought so so then let me check theta e is theta e plus lv okay so this cup da 18 okay so what omega s by cpt akil the funda is whether theta e has to be greater than theta or it cannot be from your thing it is less than it is some theta into e to the power of some positive quantity which should be greater than 1 so it already is plain wrong it is not on it's not correct isn't it yes how can it be it's e to the power of something a very small quantity also is more than 1 therefore in principle theta e is always greater than theta so when you say 30 degrees and this is 18 degrees it is not correct no please don't make mistakes make mistakes omega s will be in grams per kilogram multiply by 10 to the power of minus 3 lv will be in kilo joules attention please lv will be 2 to 5 0 kilo joule would omega will be in grams per kilogram into 10 to the power of minus 3 so that 10 to the power of minus 3 and this 10 to the power of plus 3 will get cancelled all right so what is it which is it what are you getting you should get some decent values rohan cp is 1 1 0 0 4 if you take 1.00 it is kilo joule um 30 very good at b we'll complete this go on case today one class we have just solved the sounding problem degree Celsius at kelvin sir which one theta they have converted finally temperature is this one which temperature is this one theta will be in kelvin can be theta in kelvin subtract 73 and get it man those things from childhood you are doing when you are operating when you are operating on thetas you can um 73.2 how that is not correct no yes sir uh how much is it okay yeah 342 um let's not get into that argument now we'll assuming that that formula is correct let's finish this um i should have given this as an exercise problem yeah how much is it 103 is it correct i am not sure okay theta i b 105 are you getting uh i am not sure then theta i b yeah that is all right the t have used in kelvin right here cp kelvin is into 10 to the power of 3 omega is 10 to the power of minus 3 cp i thought it will give small values omega is is how much uh so 2250 can i correct into what is t how much is this it will come 18 tell me how much is this please tell me how much is this value no no that's this value what is this value just tell me 0.22 so what is the t to the power of 0.22 is this correct rohan just check the values no somebody told me it's 13 come on how can it vary so much for a it is 18 for b i omega s is the omega corresponding to the dew point omega s is the saturation mixing ratio that comes only from the blue line this is not lv omega it is lv omega s hey baba how will you find omega s at a point unless you know the dew point what is it after listening to the whole ramayana your how will you get the omega s unless you know the dew point you can't know the saturation condition given a point a can you find the saturation mixing ratio it is not possible that is why the sounding for dew point is also given please get your funda straight the omega at point a is not known simple the omega at point a any point is not known the saturation at all these points are known through the dew point please understand the sounding right so if you take at a you will get 30 40 50 high values of omega that is not correct what is the omega corresponding to td 18 so that is a correct value let us use this then the whole thing is this is point 113 point how much is point okay so theta e a is okay theta e b another three minutes we will finish this theta e b get the omega s at b and then substitute and then you have the theta should be less should be less correct no no we don't know so it is stable it's stable right yeah yeah check it check it so you're using 26 now 26 degrees which is like 299 299 e to the power of 2250 new omega s will be lower because your mood left new omega s will be lower t is also lower yeah doh theta e by doh is that is so it is convectively so it is convectively unstable correct very good correct got it what do you mean by is there a contradiction is there a contradiction between the part a and part b part a I told you that a b oh part a was also unstable then no problem because here the check no gamma is great with the gamma d so left to itself left to attention please left to itself whether the parcel will be stable or not is decided by gamma greater than gamma d less than gamma d and all that this elaborate calculation of theta e is if the parcel is pushed whether eventually it will become unstable it will lead to some cumulus clouds and rain by sustained vertical motion if you just push it what will eventually happen to it that so that study is a study of convective instability is it okay now you see you are struggling a lot so for 8 levels it will take at least 20 minutes to find out the convective stability in 5 or 7 minutes you will find a normal stability and then another 5 minutes to do the plotting so 30 to 35 minutes if you don't make mistakes and if you are fine with the kilo joules and grams per kilogram and all that you should be able to because you are not going to do it 16 times don't worry man if you are doing a b for b c b is already there for b c already b is there for c d that c will be there so you don't have to do double calculations for each of this