 Hello and welcome to the session. In this session we are going to discuss the following question and the question says that convert 3-j4 in polar form. We know that polar form of a plus jb is equal to r into cos theta plus j sin theta the whole. Also modulus r is equal to under root of a square plus b square where r is pretty greater than 0 and amplitude theta is equal to tan inverse b by a. With this key idea let us proceed with the solution. We are given 3-j4 in the a plus jb form. We have to convert this into the polar form that is in r into cos theta plus j sin theta form. On comparing 3-j4 with a plus jb we get a is equal to 3 and b is equal to minus 4. So to convert it into polar form we first find modulus r. From the key idea we know that modulus r is equal to under root of a square plus b square where r is strictly greater than 0. Putting the values of a and b we get r is equal to under root of 3 square plus minus 4 whole square where r is strictly greater than 0. This is equal to under root of 9 plus 16 which is equal to under root 25 which will be equal to 5 as r is strictly greater than 0. So we have r is equal to 5. Now we find the amplitude theta. From the key idea we know that the amplitude theta is equal to tan inverse b by a. So by putting the values of a and b we get theta is equal to tan inverse minus 4 by 3. This implies that theta is equal to minus 53.13 degrees. Here the negative sign of theta also shows that the complex number will lie in the fourth quadrant. So polar form of 3 minus j4 is equal to r into cos theta plus j sin theta the whole. We have already found out the values of r and theta that is r is equal to 5 and theta is equal to minus 53.13 degrees. When we put the values of r and theta we get 3 minus j4 is equal to 5 into cos of minus 53.13 degrees plus j sin minus 53.13 degrees the whole. So this is our required answer. This completes our session. Hope you enjoyed this session.