 Hello and welcome to the session. In this session we discussed the following question which says a number of two digits has two for its units digit and the sum of the digits is 1 upon 4 of the number itself. What is the number? Before we move on to the solution, let's see one fact which says that a two digit number a b in which b is the units digit, a is the tenth digit is written in the general form as 10 into a plus b. This is the key idea for this question. Now let's move on to the solution. In the question we are given that the units digit is given as 2 where 0 let the tenth digit be equal to x. So now we have got the tenth digit also that is x and the units digit that is 2. So the two digit number is given by 10 into the tenth digit that is x plus the units digit that is 2 this is equal to 10x plus 2. So this is the number formed when we have the units digit as 2 and the tenth digit as x. Now the sum of the digits that is sum of the units digit and the tenth digit is given as 2 plus x. Now according to the question we have that the sum of the digits is one fourth of the number itself. So this means we have 2 plus x is equal to 1 upon 4 of the two digit number formed that is 10x plus 2. So this further gives us 4 into 2 plus x is equal to 10x plus 2 that is 8 plus 4x is equal to 10x plus 2. This gives us 10x is equal to 8 minus 2 which is further equal to 6x is equal to 6. So on dividing both sides by 6 we get x is equal to 1. Now we have assumed the tenth digit to be x. So we get the tenth digit is equal to 1 and we have already given the units digit as 2. The required number is equal to 10 into the tenth digit that is 1 plus the units digit that is 2. This is equal to 10 plus 2 equal to 12. The answer is 12 is the required number. So this completes the session. Hope you understood the solution for this question.