 Hi and welcome to the session. Let us discuss the following question. The question says in each of the exercises 7 to 12, find the equation of the parabola that satisfies the given conditions vertex 00. Passing through point 23 and axis is along x-axis. Before solving this question, we should know that if the vertex of the parabola is at the origin and focus is at the point A0, now A0 means that the parabola lies on the positive side of the x-axis. Its axis of symmetry is x-axis. Then equation of this parabola is of the form pi squared equals to 4Ax and this parabola opens to the right. Keeping this in mind, let's now begin with the solution. We are given that vertex is 00. Parabola is passing through point 23 and axis is along x-axis. So the required parabola is passing through point 23 and its axis is along x-axis. Required parabola on the positive side of the axis since the point 23 lies on the first quadrant. Now as the parabola lies on the positive side of x-axis, so this implies that focus also lies on the positive side of x-axis. As focus lies on the positive side of x-axis, so this implies required equation parabola is of the form is passing through the point 23. So now we will put x as 2 and y as 3 in this equation. By substituting values of x and y, we get 9 is equal to 8A. This implies A is equal to 9 by 8. Now we will substitute A equals to 9 by 8 in standard equation of parabola that is y squared equals to 4Ax. Now by substituting value of A, we get y squared is equal to 4 into 9 by 8 into x. This implies y squared is equal to 9 by 2x and this implies 2y squared is equal to 9x. So required equation of parabola is 2y squared is equal to 9x. This is our required answer. So this completes the session. Bye and take care.