 Hello and welcome to the session. The question says, A and B are two wins such that probability of A is 0.54, probability of B is 0.69 and probability of A intersection B is 0.35. Find, first, probability of A union B, second, probability of A dash intersection B dash, third, probability of A intersection B dash and fourth, probability of B intersection A dash. Let us now start with the solution. First we have to find probability of A union B and this is equal to probability of A plus probability of B minus probability of A intersection B. If A and B are any two wins, now let us substitute the values of probability of A, probability of B and probability of A intersection B. So, it is 0.54 plus 0.69 minus 0.35 and this is further equal to 0.88. The answer to the first part is 0.88. Now, let us proceed on to the second part. Here we have to find probability of A dash intersection B dash. This is equal to 1 minus probability of A union B and probability of A union B just now. You find in the first part it is equal to 0.88. So, we have 1 minus 0.88 which is equal to 0.12. So, answer to the second part is 0.12. Now, let us proceed on to the third part. Here we have to find probability of A intersection B complement. This is equal to probability of A minus probability of A intersection B and this is further equal to probability of A is given to us 0.54 minus probability of A intersection B is 0.35 and I am simplifying it. We get 0.19. Hence, answer to the third part is 0.19 and now proceeding on to the last part. Here we have to find probability of B intersection A complement and this is equal to probability of B minus probability of A intersection B and probability of B is equal to 0.69 minus probability of A intersection B is 0.35. So, this is equal to 0.34 and hence the answer to the last part is 0.34. So, this completes the session. Bye and take care.