 Hi, and welcome to the session I am Deepika here. Let's discuss a question which says find the general solution of the following differential equation. dy by dx plus y over x is equal to x square. Let's start the solution. Now, the given differential equation is dy by dx plus y over x is equal to x square. Let us give this equation as number one. Now, this equation is of the form dy by dx plus py is equal to q where x is equal to 1 over x and q is equal to x square. Therefore, the integrating factor is equal to e raise to power integral of p ds and this is equal to e raise to power integral of 1 over x ds and this is equal to e raise to power log x which is equal to x. Now, on multiplying both sides of equation one by the integrating factor we get dy by dx into x plus y over x into x is equal to x square into x dy by dx into x plus y is equal to x square. Now, the left hand side of this equation is a differential of function xy. So, this equation can be written as dy dx of xy is equal to x square. Now, integrating both sides with respect to x we have integral of d over dx of xy dx is equal to integral of x cube dx or py is equal to x raise to power 4 over 4 plus c. Hence, the general solution of the given differential equation is xy is equal to x raise to power 4 over 4 plus c and this is our answer for the above question. I hope the solution is clear to you and you have enjoyed the session. Bye and see you.