 Hello and welcome to the session. In this session we discussed the following question which says construct a parallelogram PQRS in which diagonal PR is equal to 3.8 centimeters, diagonal QS is equal to 4.6 centimeters and the angle between PR and QS is 60 degrees. Before proceeding with the solution let's recall the fact which says that the diagonals of a parallelogram bisect each other. This is the key idea that we use in this question. Let's proceed with the solution now. First we will construct the rough sketch of the parallelogram PQRS. Consider this parallelogram PQRS where we have the diagonal PR is of measure 3.8 centimeters and the diagonal QS is of measure 4.6 centimeters and the angle between the two diagonals PR and QS say this angle is of measure 63 degrees. Now we shall construct the parallelogram step by step. Now in the first step we draw diagonal equal to 3.8 centimeters. So this is the diagonal PR of the parallelogram PQRS of measure 3.8 centimeters. Now since we have that the diagonals of parallelogram bisect each other so in the next step we will bisect PR at O. So we have bisected the diagonal PR at this point O that is we have PO is equal to OR equal to 1.9 centimeters. Now since it's given that the angle between the two diagonals is of measure 60 degrees. So what we do is in the next step we make angle OX equal to 60 degrees. So this angle ROX is of measure 60 degrees. In the next step we produce XO2Y. So we have produced this XO2Y. Now in the next step width center and radius equal to half of now which is equal to half of 4.6 that is equal to 2.3 centimeters. We cut an arc on the ray so we have drawn these two arcs on the ray OX also and on the ray OY also at this point of intersection of the arc and the ray OX be point S and this point of intersection of the arc and the ray OY be Q. Then in the next step we join PQ after joining PQ, QR, RS and SP we get PQ, RS, SC required parallelogram. And in this we have diagonal PR is equal to 3.8 centimeters, diagonal QS is equal to 4.6 centimeters and angle between the two diagonals say angle ROX is equal to 60 degrees. Thus we have RS is the required parallelogram. Hope you have understood the solution for this question.