 Hello and welcome to the session. Let us understand the following question today. Two poles of height 6 meters and 11 meters stand on a plain ground. If the distance between the feet of the poles is 12 meters, find the distance between their top. Now let us see the diagram. Here we have two poles of height 11 meters, let AB be the pole of height 11 meters and let CD be the pole of height 6 meters. And the distance between the feet of the two poles is 12 meters and the distance between D and V is 12 meters. And we have to find the distance between the top, that is AC. Now we have joined CE. Draw CE perpendicular to AB. Here CE is perpendicular to AB. Therefore CE is equal to BD, which is equal to 12 meter. And AE is equal to AB minus BE, that is AE is equal to AB minus CD, because BE is equal to CD. That is AE is equal to 11 minus 6, which is equal to 5 meter. Now consider right angled triangle, ACE, which is right angle at E. So therefore by Pythagoras theorem, we have AC square is equal to CE square plus AE square. That is AC square is equal to CE is 12, so 12 square plus AE is equal to 5, so plus 5 square. Which implies AC square is equal to 144 plus 25, which implies AC square is equal to 169, which implies AC is equal to 13. Hence the distance between the tops of the two poles is 13 meter, that is the required answer is 13 meter. I hope you understood the question. Bye and have a nice day.