 Hi and welcome to this session. Let us test the following question. The question says a right triangle ABC with sides 5 cm, 12 cm and 13 cm is revolved about the side 12 cm. Find the volume of the solid so obtained. Let's now begin with the solution. Now suppose this is the right triangle ABC in which AD is equal to 12 cm, DC is equal to 5 cm and AC is equal to 13 cm. Now the question says that this right triangle is revolved about the side AB. Right, we have to find the volume of the solid so obtained. We know that the solid generated by the rotation of a right-angled triangle about one of the sides containing the right angle is called the right circular code. So, on revolving the right triangle ABC above the side AB which is equal to 12 cm we will get like this whose height is 12 cm and base radius is 5 cm. We will find the volume of the code generated. Now here height that is h is equal to 12 cm and base radius that is r is equal to 5 cm. You know that volume of the code generated is equal to 1 by 3 pi r square h. By substituting the values of r and h we get 1 by 3 into pi into 5 into 5 into 12 cm q. On cancelling 12 by 3 we get 4 so this is equal to 100 pi cm q. Hence the volume of the code generated is 100 pi cm q. This is our required answer. So, this completes the session. Bye and take care.